For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB
Hence, The average of these absolute deviations is 3.5.
Answer:
is the questions even correct? recheck the units
Answer:
size because when a figure is squeezed, it shrinks and changes the size
Answer:
-32
Step-by-step explanation:
9(-3) + (-15) ÷ 3 =
-27 + -5 = -32
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-Chetan K
