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WINSTONCH [101]
3 years ago
15

What is the answer of this attachment:

Mathematics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

(B) 2

Step-by-step explanation:

=> \frac{\sqrt{32}+ \sqrt{48} }{\sqrt{8}+\sqrt{12}  }

=> \frac{4\sqrt{2}+4\sqrt{3}  }{2\sqrt{2}+2\sqrt{3}  }

=> \frac{4(\sqrt{2}+\sqrt{3})  }{2(\sqrt{2}+\sqrt{3)}  }

Cancelling \sqrt{2}+\sqrt{3}

=> \frac{4}{2}

=> 2

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Answer:

30°

Step-by-step explanation:

•angle 8 would be the same as angle 6

•angle 6 is next to angle 3

•if you were to add angle 6 and 3 it should equal 180°

180-150=30°

i rlly hope this is correct and helps <3

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What should the first step be when solving for x?<br>-5x+6(-2x-13)=7​
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multiply the things in the () with6

Step-by-step explanation:

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A researcher is concerned about the impact of students working while they are enrolled in classes, and she likes to know if stud
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Answer:

(a) Point estimate = 7.10

(b) The critical value is 1.960

(c) Margin of error = 0.800

(d) Confidence Interval = (6.3, 7.9)

(e) We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

Step-by-step explanation:

Given

\bar x = 7.10 -- sample mean

\sigma=5 --- sample standard deviation

n = 150 --- samples

Solving (a): The point estimate

The sample mean can be used as the point estimate.

Hence, the point estimate is 7.10

Solving (b): The critical value

We have:

CI = 90\% --- the confidence interval

Calculate the \alpha level

\alpha = 1 - CI

\alpha = 1 - 90\%

\alpha = 1 - 0.90

\alpha = 0.10

Divide by 2

\frac{\alpha}{2} = 0.10/2

\frac{\alpha}{2} = 0.05

Subtract from 1

1 - \frac{\alpha}{2} = 1 - 0.05

1 - \frac{\alpha}{2} = 0.95

From the z table. the critical value for 1 - \frac{\alpha}{2} = 0.95 is:

z = 1.960

Solving (c): Margin of error

This is calculated as:

E = z * \frac{\sigma}{\sqrt n}

E = 1.960 * \frac{5}{\sqrt {150}}

E = 1.960 * \frac{5}{12.25}

E =  \frac{1.960 *5}{12.25}

E =  \frac{9.80}{12.25}

E =  0.800

Solving (d): The confidence interval

This is calculated as:

CI = (\bar x - E, \bar x + E)

CI = (7.10 - 0.800, 7.10 + 0.800)

CI = (6.3, 7.9)

Solving (d): The conclusion

We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

6 0
3 years ago
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