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WINSTONCH [101]
3 years ago
15

What is the answer of this attachment:

Mathematics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

(B) 2

Step-by-step explanation:

=> \frac{\sqrt{32}+ \sqrt{48} }{\sqrt{8}+\sqrt{12}  }

=> \frac{4\sqrt{2}+4\sqrt{3}  }{2\sqrt{2}+2\sqrt{3}  }

=> \frac{4(\sqrt{2}+\sqrt{3})  }{2(\sqrt{2}+\sqrt{3)}  }

Cancelling \sqrt{2}+\sqrt{3}

=> \frac{4}{2}

=> 2

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What’s the correct answer
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----------------------------------------------------------------------------
Find constant a.
----------------------------------------------------------------------------
Given that g(4) = 8

--------------------------------------
Substitute x = 4
--------------------------------------
g(4) = a(4)² + 24 = 8

16a + 24 = 8

--------------------------------------
Take away 24 from both sides
--------------------------------------
16a = 8 - 24

16a  = -16

--------------------------------------
Divide by 16 on both sides
--------------------------------------
a = -1

Now that we know that a = -1, plug it back to the equation.

g(x) = -x² + 24

--------------------------------------
Find g(-4)
--------------------------------------
g(-4) = - (-4)² + 24
g(-4) = -16 + 24
g(-4) = 8

----------------------------------------------------------------------------
Answer: 8
----------------------------------------------------------------------------


8 0
3 years ago
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