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liberstina [14]
3 years ago
9

What is another way to write 2.50%?

Mathematics
1 answer:
Amanda [17]3 years ago
6 0
Uh! Maybe just 2.50/100 = 0.025 (without the % symbol)
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Help? Plz I need help
e-lub [12.9K]

Remark

If you really take this question seriously, you will stop tailgating immediately. Being any less than 6 car lengths away from the car in front of you is dangerous even if you are paying attention, never mind if you are not.

Conversion

\dfrac{60 miles}{hour}*\dfrac{5280 feet}{1 mile}* \frac{1 hour}{3600 seconds}

Now just multiply all the numerators together

60 * 6280 * 1 = 316800

And then multiply all the denominators together

1 * 1 * 3600 = 3600

Divide the numerators / denominators to get 316800/3600 = 88 feet / second

If you go 88 feet in 1 second you will go 88 * 4 feet in 4 seconds which is 352 which is about the length of a football field. It is an awfully long way to be inattentive.


3 0
4 years ago
Joanna ran a mile in physical education class. After resting for one hour, her heart rate was 60 beats per minute. If her heart
Ugo [173]
So, if 60 beats was decreased by 2/5 before, we know that 60 beats = 3/5 of her heart rate after she ran the mile.

(Because 1 - 2/5 = 3/5)

So, 3/5 = 60, and we're trying to find 1.

So I would first divide both sides by 3.

3/5 = 60
/3      /3

1/5 = 20

Then multiply both sides by 5.

1/5 * 5 = 20 * 5

1 = 100

So her heart rate was 100 beats per minute immediately after she ran the mile.
4 0
3 years ago
Find m&lt;1<br> 33°<br> 28°<br> 42°<br> 47°
marissa [1.9K]

Answer:

it's answer is 33°

Step-by-step explanation:

116° + 31° + m<1 = 180° [being sum of angles of triangle ]

147° + m< 1 = 180°

m<1 = 180° - 147°

m<1 = 33°

hope \: i t \: will \: help

5 0
3 years ago
Common factors of 50,30,100
umka21 [38]
Common factors of 50: 1, 2, 5, 10, 25, 50
Common factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
Common factors of 100: 1, 2, 4, 5, 10, 20, 25, 50, 100

You're welcome.
6 0
4 years ago
Read 2 more answers
Ms. Carr's Class Is Selling Magazines To Raise Money For A Field Trip. The Students In The Class Device They Wanted To Make 5.50
FinnZ [79.3K]

Here you are giving only the amount they want to raise (namely profit times number of magazines sold), and here you are also giving Money they want to raise... So clarifying, the money they want to raise, should include the money they will spend on buying the magazines (there is no statement saying they found them, or were given the magazines, so a cost should be involved) 

Now if they are only making the count of "Field trip costs X amount of money, and given we have to make a profit of $5.5, How many must we sell?" then the equation should be n=X/5.5 

Should the story be, how much money must they raise to have a profit of 5.5 on each magazine and still have enough for the field trip, then you have a different equation which varies only in adding the cost of each magazine, either case, M should be defined not as money they need to raise (cause here they will be short on their goal) but Money they must earn. And again, you should rewrite your equation to be: 

M=Amount they must raise 
C=Cost per magazine 
n=Number of magazines 
p=profit $5.5 per magazine 

C+p=M/n 

And rewriting the previous they should make: 

n(C+p)=M -----> n(C+5.5)=M <span>m/n = 5.50 </span>
<span>m/n x n = 5.50 x n //// multiply each side by n </span>

<span>m = 5.5n</span>
6 0
3 years ago
Read 2 more answers
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