All categories

2 years ago

Graph this function: y =3/4x - 4 (you can just put the cordinants)

Mathematics

1 answer:

Aloiza [94]2 years ago

5 0

I’m assuming 3/4x is a fraction
the coordinates are (0,-4) and (4,-1)

You might be interested in

Geetika bought 15.40m long cloth. The tailor cuts 11m and 5cm for dress and 2m 3 cm for a shirt and returned the remaining cloth

amm1812

Answer:

The length of cloth Geeka got is 2.32m

Step-by-step explanation:

The length Geetika got can be calculated by deducting the total length the tailor cuts from the initial length of the cloth.

Initial length of cloth = 15.40m

From the question, the tailor cuts 11m and 5cm for dress and 2m 3 cm for a shirt.

Therefore, the total length the tailor cut = 11m 5cm + 2m 3cm = 13m 8cm

NOTE: 13m 8cm = 13.08m

The length Geeka got = 15.40m - 13.08m = 2.32m

Hence, the length of cloth Geeka got is 2.32m

4 0

2 years ago

Mick deposit $1,000

Ulleksa [173]

Answer:

Step-by-step explanation:

6 0

2 years ago

What are the missing letters in the pattern? kr, np, _____ , tl , wj, ...

maria [59]

Your answer is , qn.

4 0

2 years ago

What value of n makes the equation true?

zhannawk [14.2K]

To get the answer you have to add 29.4 and 13.9 and you get 43.3
It is A

5 0

2 years ago

Read 2 more answers

Differentiate with respect to X <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7Bcos2x%7D%7B1%20%2Bsin2x%20%7D%20

Mice21 [21]

Power and chain rule (where the power rule kicks in because $\sqrt x=x^{1/2}$ ):

$\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'$

Simplify the leading term as

$\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}$

Quotient rule:

$\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}$

Chain rule:

$(\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)$

$(1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)$

Put everything together and simplify:

$\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}$

$=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}$

$=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}$

5 0

2 years ago

Graph this function: y =3/4x - 4 (you can just put the cordinants)​

Graph this function: y =3/4x - 4 (you can just put the cordinants)