Question

Triangle ABC is an isosceles triangle in which AB = AC. What is the perimeter of △ABC?

Answer 1

Answer:
perimeter = 10 + √10 units

Explanation:
First, we will need to get the length of each line using the distance formula which is as follows:
distance = $\sqrt{( x_{2}- x_{1} )^2 + ( y_{2} - y_{1})^2 }$

1- length of AB:
AB = $\sqrt{(-1--1)^2+(1-6)^2}$ = 5 units

2- length of AC
length of AC is the same as AB = 5 units

3- length of BC:
BC = $\sqrt{(2--1)^2+(2-1)^2}$ = √10 units

Now, we can get the perimeter by adding the side lengths as follows:
perimeter = 5 + 5 + √10
perimeter = 10 + √10 units

Hope this helps :)

Answer 2

okie the answer is

10 + square root of 10 units