Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Step-by-step explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
<em>Find the measure of angle EFG</em>
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
<em>Find the measure of angle GFH</em>
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°
D.) because there are 5 caterpillars in every tree (t) and then you have to add the 10 that are on the ground giving you the total amount of caterpillars (c)
<span>1st year value =45$
2nd year value=45+2.80$=47.80$
3rd year value=47.8+2.80$=50.60$
4th year value=50.60+2.80=53.40$
5th year value=53.40+2.80=56.20$
ater 5 years value of share becomes 56.20$
or
share after 5 years= 45+4*2.80=45+11.20=56.20$</span>
