How to solve 15x^3/4

Mathematics

2 answers:

valentinak56 [21]3 years ago

8 0

Answer:

Well...without the x I know it is 843.75 but I don't know the fraction of it so sorry! I try my best to help people!

Elena L [17]3 years ago

3 0

Answer:

Simplify —

Equation at the end of step

15x • —

STEP

Final result :

45x

———

Step-by-step explanation:

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The Legs of a right triangle are lengths x and x square root of 3. The cosine of the smallest angle is

ki77a [65]

Answer:

Step-by-step explanation:

hypotenuse=√(x²+(x√3)²)=√(x²+3x²)=√(4x²)=2x

sides are x,x√3,2x

smallest side=x

smallest angle=opposite smallest side

let smallest angle=α

cos α=(x√3)/2x=√3/2

4 0

3 years ago

Read 2 more answers

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .