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bulgar [2K]
3 years ago
13

The solution to 2x - 5 = 27 is also a solution of which of the following equations?

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

C) 2x+3=35

Step-by-step explanation:

Nata [24]3 years ago
5 0
The answer is
2x+3=35
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Help asap????????!!!
Veseljchak [2.6K]

Answer:

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Step-by-step explanation:

6 0
2 years ago
Which of these numbers is GREATEST? A) 5.7 × 106 B) 5.7 × 107 C) 5.07 × 106 D) 5.07 × 107
Vaselesa [24]

Answer:

B) 5.7 × 107 = 609.9

Step-by-step explanation:

A) 604.2

B) 609.9

C) 537.42

D) 542.49

3 0
3 years ago
in the northen hemisphere the ratio of tye area of the water is 2:3 work out the percentage of tge area of the northen hemispher
labwork [276]

Answer:

40%

Step-by-step explanation:

l2:w3 means that the fraction of land is 2/5.

time 2/5 by 20, you get 40/100

convert 40/100 into percentage is 40%

5 0
2 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Simplify: (x+7)(x-4)
SVETLANKA909090 [29]

Answer:

x² + 3x - 28

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor

(x + 7)(x - 4)

= x(x - 4) + 7(x - 4) ← distribute both parenthesis

= x² - 4x + 7x - 28 ← collect like terms

= x² + 3x - 28


6 0
3 years ago
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