Answer: See below.
Step-by-step explanation:
The formatting is likely incorrect for these two options:
y=(x−1)2, and
y = ( x − − 1 ) 2
I'll assume they were meant to be:
y=(x−1)^2, and
y = ( x + 1 )^2
In this case they would be non-linear, since y depends on the value of 
Use a "^" sign to indicate raised to a power: x^2 means
.
y=(x−1)2 means y = 2x - 2
y=(x−1)^2 means y = 
This is a fun problem! Just graph the two equations, then see what points the line intersects with the parabola. Or, set the two equations equal to each other, and solve for the two intersecting points.
Solve for x and y: -2x+8 = x-2.23y+10.34
Answer:
(-5,-8)
Step-by-step explanation:
If M(x,y) is the midpoint of the segment CD, where
then

You are given two points A(-2,-3) and B(1,2), let point F be the point with coordinates (x,y). Yuo know, that point A is the midpoint of BF, then

Substitute known coordinates:

So, point F has coordinates (-5,-8)
Cool I guess I’m getting none