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arlik [135]
3 years ago
7

Read the complete problem before answering. Teresa bought 2 1/2 gallons of chocolate milk at the dairy farm. Chocolate milk cost

$4.50 a gallon. How much did Teresa spend on the milk? A student solved the problem this way. gallons 2 1/2 = 2.5 gallons Let n represent the amount Teresa spent on the milk. n = 2.5 × $4.50 n = $11.25 Teresa spent $11.25. Use a similar strategy to solve this problem. Pedro bought 1 1/4 lb of red sand and 5 1/2 lb of brown sand to refill his sand box. Both types of sand cost $4.60 a pound. How much did Pedro spend on the sand?
Mathematics
1 answer:
Svetach [21]3 years ago
7 0
He spent $5.75 on the red sand and $25.30 on the brown sand he spent a total of $31.05 on sand to fill his sand box! Hope this helps you :)
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Janet unfolded a cardboard box. The figure of the unfolded box is shown below:
bixtya [17]
3rd one 10 x 6 x 6
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5 0
3 years ago
. Solve the following equations for x: 3x=30
pishuonlain [190]

\mathcal \pink{Answer}

\mathcal \green{3x = 30}

\mathcal \blue{ \frac{3x}{3}  =  \frac{30}{3} }

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3 0
3 years ago
Read 2 more answers
What is 3 1/2 - 2 5/7 and show the work
Hunter-Best [27]
3 \frac{1}{2}  -2 \frac{5}{7} = \frac{(3\cdot2)+1}{2} -  \frac{(2\cdot7)+5}{7} =  \frac{7}{2} -  \frac{19}{7} \\\\= \frac{7\times 7}{2\times 7} -  \frac{19\times 2}{7\times 2} =  \frac{49}{14} - \frac{38}{14} \\\\= \frac{49-38}{14} =\boxed{\bf{\frac{11}{14}}}
6 0
4 years ago
Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a
dolphi86 [110]

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

3 0
3 years ago
Please help me! i got this wrong and i dont know what i did wrong
Genrish500 [490]

Answer: See you have to understand the problem and then solve it Answer is: 5g - 2/10

8 0
3 years ago
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