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Sladkaya [172]
4 years ago
6

PAGE 12

Mathematics
1 answer:
Yakvenalex [24]4 years ago
3 0

Answer: The answer is option C: 10cm, 6cm and 8cm

Step-by-step explanation: A right angled triangle has an hypotenuse (the longest of all three sides) facing the 90 degree angle. Also a right angled triangle can be solved by means of the Pythagoras theorem which states that;

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse (10cm) and AB (6cm) and BC (10cm) are the other two sides.

If that is the case, we can insert the values as given in option C to know whether or not they make up a right angled triangle. Therefore

10^2 = 6^2 + 8^2

100 = 36 + 64

100 = 100

Therefore the side lengths 10cm, 6cm and 8cm satisfies the requirements for a right angled triangle

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Answer:

615.75216

Step-by-step explanation:

A=πr2

=π·14^2

≈615.75216

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What is the equation of the line in point slope form with
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Answer:

y = 3/4x + 17/4

Step-by-step explanation:

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1/2+(-5/6)+1/4<br><br> -7/12<br> -1/12<br> 1/12<br> 1 7/12
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What's 5x + 5y = - 20 in slope form
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P= (x,y) is an arbitrary point on the circle x^2+y^2=36
sesenic [268]

Let (x,y) be an arbitrary point on the circle.

Then d = √[x-3)2 + (y-0)2] = √[x2 - 6x + 9 + y2]

Since x2 + y2 = 1, y2 = 1-x2.

So, d = √[x2 - 6x + 9 + 1 - x2]

     d = √(-6x+10)

Domain:  x is the x-coordinate of a point on the circle centered at (0,0) with radius 1.  So, -1≤x≤1.

             But, for d to be defined, we need -6x+10 ≥ 0.  So, x ≤ 5/3  (True for all x in [-1,1]).

             Domain = [-1,1]

Range:    -1 ≤ x ≤ 1   So, 6 ≥ -6x ≥ -6

                                    16 ≥ -6x+10 ≥ 4

                                     4 ≥ √(-6x+10) ≥ 2   That is, 2 ≤ d ≤4

              Range:  [2,4]

Step-by-step explanation:

3 0
3 years ago
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