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mestny [16]
4 years ago
11

Rameen’s heating bill is $5.42 per month plus $1.08 per therm. How many therms can Rameen use if he wants his heating bill to be

a maximum of $87.50? Write the solution in interval notation.
Mathematics
1 answer:
hammer [34]4 years ago
3 0

Write and solve an inequality:

Total(t) = $5.42 + ($1.08/therm)(t) ≤ $87.50.

First, subtract $5.42 from $87.50:  then ($1.08/therm)(t) ≤ $82.08

Next, divide both sides by $1.08 per therm:


t ≤ ($82.08) / ($1.08/therm) = 76 therms (maximum).  Thus, Rameen's usage could be [0,76] (therms).

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Answer:

<em></em>Area = 72in^2<em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

<em></em>Area_2 = 8in * 12in<em></em>

<em></em>Area_1 = 96in^2<em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em>Area_2 = \frac{1}{2} * base * height<em></em>

<em></em>Area_2 = \frac{1}{2} * (6in + 6in) * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 12in * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 48in^2<em></em>

<em></em>Area_2 = 24in^2<em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

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<em></em>

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