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grandymaker [24]
3 years ago
14

I'm confused, can someone help me?

Mathematics
1 answer:
iragen [17]3 years ago
3 0

\bf \begin{array}{rll} \stackrel{standard}{notation}&\stackrel{scientific}{notation}\\ \cline{1-2} 7000&7\times 10^3\\ 700&7\times 10^2\\ 70&7\times 10^1\\\\ \boxed{7}&\boxed{7\times 10^0}\\\\ 0.7&7\times 10^{-1}\\ 0.07&7\times 10^{-2}\\ 0.007&7\times 10^{-3} \end{array}

recall, for the scientific notation, it has to be using some power of 10, and the exponent of the base 10, is how many slots you're away from the <u>decimal point</u>.  0.007 uses 10⁻³ because 7.0 or 7. when we make it 0.007, we have to move the decimal point from in front of the 7 3 slots over to the left.  Likewise, the 7000 is using 10³, because we moved the dot from 7. to 7000. , namely 3 slots to the right.

the missing value is there in the middle, notice is "7".

well, we can say that 7 is using 10⁰, however most of the time the 10⁰ is omitted and we settle for 7 alone, however scientific notation wise, that'd be it.

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strojnjashka [21]

Answer:

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Step-by-step explanation:

number 2 the answer is b

4 0
3 years ago
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2×8=16 bring down the 6 carry the one 2×1=2+1=3 so you have 36
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The sum of two numbers is 68 and the difference is 12. What are the numbers? Larger number: Smaller number:
Lady_Fox [76]

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This is hard asfk

Step-by-step explanation:

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3 years ago
Find the sum and product of zeroes of the quadratic polynomial 3x² + 5x-2.​
Alex17521 [72]

Answer:

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7 0
3 years ago
How much does a chicken cost and duck?
Firdavs [7]

Answer:

Chicken is $8

Duck is $5

Step-by-step explanation:

Step 1: Let x represent the cost of chickens and let y represent the cost ducks. Since we have two unknowns, we need two equations to find them.

Step 2: The total cost of chickens Michael sold last month can be shown as 50x, and the total cost of ducks he sold last month can beshown as 30y Since these together add up to 550, we get these equations:

50x+30y = 550

We are also given that this month, Michael sold 44 chickens, and 36start text, 36 ducks, $532. This equaion can be expressed as:

44x+36y=532

Now that we have a system of the two equations, we can now go ahead and solve the two equations.

Step 3: We can now solve the system of equations by using the elimination method. Manipulate the equations so one of the variables has the same coefficients but with opposite signs.

-6*50x+(-6)*30y\\=-300x-180y\\=-6*550\\=-3300                  5*44x+5*36y\\=220x+180y\\=5*532\\=2660

Now eliminate y

-300x-180y=-3300\\+220x+180y=2660\\=-80x-0=-640

When we solve the resulting equation, we obtain that x=8. Then, we can substitute this into one of the original equations and solve for y to obtain y=5.

Step 4: Recall that x denotes the cost of a chicken and y denotes the cost of a duck. Therefore, a chicken costs $8, and a duck costs $5

7 0
3 years ago
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