We need to satisfy the following equations:
x*y = 13
x + y = -14
Isolating x from the first equation,
x = -14 - y
Substituting this result into the first equation,
(-14 - y)*y = 13
-14y- y*y = 13
-y² - 14y - 13 = 0
Using the quadratic formula,
![\begin{gathered} y_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ y_{1,2}=\frac{14\pm\sqrt[]{(-14)^2-4\cdot(-1)\cdot(-13)}}{2\cdot(-1)} \\ y_{1,2}=\frac{14\pm\sqrt[]{144}}{-2} \\ y_1=\frac{14+12}{-2}=-13 \\ y_2=\frac{14-12}{-2}=-1 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y_%7B1%2C2%7D%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D%20%5C%5C%20y_%7B1%2C2%7D%3D%5Cfrac%7B14%5Cpm%5Csqrt%5B%5D%7B%28-14%29%5E2-4%5Ccdot%28-1%29%5Ccdot%28-13%29%7D%7D%7B2%5Ccdot%28-1%29%7D%20%5C%5C%20y_%7B1%2C2%7D%3D%5Cfrac%7B14%5Cpm%5Csqrt%5B%5D%7B144%7D%7D%7B-2%7D%20%5C%5C%20y_1%3D%5Cfrac%7B14%2B12%7D%7B-2%7D%3D-13%20%5C%5C%20y_2%3D%5Cfrac%7B14-12%7D%7B-2%7D%3D-1%20%5Cend%7Bgathered%7D)
Therefore, the solution is:
Answer:
Formula for area is length times width
So 2x × x = 2x^2
E. G.
2×2×2=8
And can also be written as 2^3
Meaning 2×2×2
So in this instance x × x=x^2
In front of the length x imagine a 1
So 2×1=2
Therefore 2x^2
The answer to this question is a simple one.
First, you need this formula :
<span>(<span>x0 </span>+ dx<span>)^2
You need to substitute the values of the formula
Then,.
</span></span><span>(dx)^2 = (0.06)^2
So the answer to this question is .0036
I hope my answer helped you in somehow. </span>
Answer:
x=-4/9, y=10/3. (-4/9, 10/3).
Step-by-step explanation:
3x+4y=12
3x=2y-8
--------------
2y-8+4y=12
6y-8=12
6y=12+8
6y=20
y=20/6
simplify,
y=10/3
3x=2(10/3)-8
3x=20/3-8
3x=20/3-24/3
3x=-4/3
x=(-4/3)/3
x=(-4/3)(1/3)=-4/9
x=-4/9, y=10/3. (-4/9, 10/3).
Answer:
<em>V = 1,568</em>
Step-by-step explanation:
<u>The Volume of a Square Pyramid</u>
Given a square-based pyramid of base side a and height h, the volume can be calculated with the formula:

We are given a square pyramid with a base side a=14 ft but we're missing the height. It can be calculated by using the right triangle shown in the image attached below, whose hypotenuse is 25 ft and one leg is 7 ft
We use Pythagora's theorem:

Solving for h:


The height is h=24 ft. Now the volume is calculated:

V = 1,568