Answer:
1. 0.33 2. 0.16 3. o.11
Step-by-step explanation:
Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
Answer:
See Explanation
Step-by-step explanation:
According to the Question,
Steps of construction:
- Step I - Draw a line segment AB = 7 cm with the help ruler.
- Step II - with vertex A, by using compass take more than half of AB and draw arcs, one on each side of AB.
- Step III - with vertex B, by using a compass with the same length, cut the previous arcs at X and Y respectively.
- Step IV - with help of the ruler join the points X and Y Thus XY is the perpendicular bisector of line AB.
(For Diagram please find in attachment)