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azamat
3 years ago
11

Using either the integral, limit comparison, comparison, or p-test, determine if the series converges or diverges. ∑n=3→∞

rc="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%28x%2B1%29%5E2ln%28x-1%29%7D" id="TexFormula1" title="\frac{1}{(x+1)^2ln(x-1)}" alt="\frac{1}{(x+1)^2ln(x-1)}" align="absmiddle" class="latex-formula">

Mathematics
1 answer:
bija089 [108]3 years ago
5 0

Answer:

See below. The series converges.

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
B is the midpoint of AC
Usimov [2.4K]

Answer:

11x - 10

Step-by-step explanation:

ab is half the line and bc is the other half

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3 years ago
9. Use the graph of each polynomial function to find the factored form of the related polynomial.
kifflom [539]

Answer:

The zeros are the points on the x-axis where the graph intersects.

For factorization, you do (x - the zero) for each zero, and multiply them together.

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Step-by-step explanation:

6 0
3 years ago
Which of the following terms can be combined in this expression?
wlad13 [49]

Answer:

Option (3) is correct .

We can combine 6.2y with -\frac{3}{8}y  

Step-by-step explanation:

      Consider the given expression -13-\frac{x}{5}+6.2y+20.5x-\frac{3}{8}y  

We have to find the two terms can be combined in this expression.

We can combine those term which have same variable with same degree.

Here, since degree of each variable is 1 and contain two variables x and y.

So we can combine x terms together and y terms together as ,

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6 0
3 years ago
Change this radical to an algebraic expression with fractional exponents.
borishaifa [10]

Answer:

The exponent of y is 1

Step-by-step explanation:

Given

\sqrt{y^2

Required

Convert to fractional exponent

Here, we simply apply the following law of indices:

\sqrt{x^m} = x^{\frac{m}{2}}

So, the expression becomes:

\sqrt{y^2} = y^{\frac{2}{2}}

\sqrt{y^2} = y^1

\sqrt{y^2} = y

<em>From the above expression, the exponent of y is 1</em>

8 0
3 years ago
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