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Snezhnost [94]
4 years ago
15

Solve for X in the equation x^2-12x+59=0

Mathematics
2 answers:
frez [133]4 years ago
7 0
<h2>Answer:</h2>

The value of x will be:

x=6+\sqrt{23}i,\ and\ x=6-\sqrt{23}i

<h2>Step-by-step explanation:</h2>

We are given a quadratic equation in terms of the variable x as follows:

x^2-12x+59=0

We know that any quadratic equation of the form:

ax^2+bx+c=0

has solution of the type:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here,

a= 1 , b= -12 and c=59

Hence, we have the solution as:

x=\dfrac{-(-12)\pm \sqrt{(-12)^2-4\times 1\times 59}}{2\times 1}\\\\x=\dfrac{12\pm \sqrt{144-236}}{2}\\\\x=\dfrac{12\pm \sqrt{-92}}{2}\\\\x=\dfrac{12\pm 2i\sqrt{23}}{2}\\\\x=6\pm \sqrt{23}i

nikdorinn [45]4 years ago
4 0

Answer:

X = -4.917

Step-by-step explanation: The goal is when solving for a variable is to get it by itself.  First subtract 59 from +59 on the left side and do the same on the right side of the equation. Now you have 12x = -59.  

X is multiplied by 12 and to get X by itself we do the opposite, which is divide. Divide 12x by 12 and divide -59 by 12. X = -4.917


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