Question

Solve for X in the equation x^2-12x+59=0

Answer 1

Answer:

The value of x will be:

$x=6+\sqrt{23}i,\ and\ x=6-\sqrt{23}i$

Step-by-step explanation:

We are given a quadratic equation in terms of the variable x as follows:

$x^2-12x+59=0$

We know that any quadratic equation of the form:

$ax^2+bx+c=0$

has solution of the type:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here,

a= 1 , b= -12 and c=59

Hence, we have the solution as:

$x=\dfrac{-(-12)\pm \sqrt{(-12)^2-4\times 1\times 59}}{2\times 1}\\\\x=\dfrac{12\pm \sqrt{144-236}}{2}\\\\x=\dfrac{12\pm \sqrt{-92}}{2}\\\\x=\dfrac{12\pm 2i\sqrt{23}}{2}\\\\x=6\pm \sqrt{23}i$

Answer 2

Answer:

X = -4.917

Step-by-step explanation: The goal is when solving for a variable is to get it by itself.  First subtract 59 from +59 on the left side and do the same on the right side of the equation. Now you have 12x = -59.  

X is multiplied by 12 and to get X by itself we do the opposite, which is divide. Divide 12x by 12 and divide -59 by 12. X = -4.917