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djyliett [7]
2 years ago
14

A computer is on sale for 80% of the original price. If the computer originally cost $400, what is its sale price?

Mathematics
2 answers:
Flauer [41]2 years ago
8 0

Answer:$80

Step-by-step explanation:

$400x0.80=$320 off

400-320=$80

Or

$400 x 0.20= $80 sale price

Dominik [7]2 years ago
4 0

Answer:

$320

Step-by-step explanation:

400*0.8(decimal form of 80%) = 320

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3 years ago
Consider the differential equation:
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(a) Take the Laplace transform of both sides:

2y''(t)+ty'(t)-2y(t)=14

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where the transform of ty'(t) comes from

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This yields the linear ODE,

-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s

Divides both sides by -s:

Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}

Find the integrating factor:

\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C

Multiply both sides of the ODE by e^{3\ln|s|-s^2}=s^3e^{-s^2}:

s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}

The left side condenses into the derivative of a product:

\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}

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y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that \frac{7t^2}2 is one solution to the original ODE.

y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7

Substitute these into the ODE to see everything checks out:

2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14

5 0
3 years ago
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3 years ago
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Answer:

x=\frac{8}{3}

Step-by-step explanation:

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Simplify.

x=\frac{8}{3}

7 0
3 years ago
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