Find the domain and range of the relation, and state whether or not the relation is a function.

2 answers:

7 0

A relation is simply a set of ordered pairs, while a function is a set of ordered pairs in which each x-coordinate has only ONE y-coordinate associated with it.

The first elements in the ordered pairs (the x-values), form the domain. The second elements in the ordered pairs (the y-values), form the range.

In the set,

{(1, 3), (2, 3), (3, 3), (4, 3)}

it is not a function, based on the definition since an x-coordinate has the same y-coordinate which is 3.

The domain is (1,2,3,4) while range is (3).

Brilliant_brown [7]3 years ago

6 0

Domain is {1 ,2,3,4}
range is {3}
it's a function because each element in x has only one image in y

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Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

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17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that $p = 0.17$

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This is P(X = 1) when n = 7. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891$

0.3891 = 38.91% probability that only one is a second

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Step-by-step explanation:

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