Find the vertex and the axis of symmetry of the graph of the function?
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So hmm check the picture below
the radius "r" is half the diameter, meaning, the diameter is 2r long
now, if the height "h" is twice "d" or 2d, then that means h = 2(2r)
thus![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}\qquad \begin{cases} h=height\\ r=radius\\ ------\\ h=2(2r) \end{cases}\implies V=\cfrac{\pi r^2[2(2r)]}{3} \\\\\\ V=\cfrac{4\pi r^3}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ah%3Dheight%5C%5C%0Ar%3Dradius%5C%5C%0A------%5C%5C%0Ah%3D2%282r%29%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%5B2%282r%29%5D%7D%7B3%7D%0A%5C%5C%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D)
the radius "r" is half the diameter, meaning, the diameter is 2r long
now, if the height "h" is twice "d" or 2d, then that means h = 2(2r)
thus
For the fifth term, n = 5.
Just replace n with 5 in the expression.
Then evaluate the expression.
Just replace n with 5 in the expression.
Then evaluate the expression.