The 3:2 ratio can be calculated by dividing the total by the sum of the factors (3 + 2) i.e. 80/5 = 16
<span>Then multiply the factors by the answer above (i.e. 3 x 16 and 2 x 16) </span>
<span>48:32
hope this helps you ! =')</span>
Answer:
a) W₁ = 78400 [J]
b)Wt = 82320 [J]
Step-by-step explanation:
a) W = ∫ f*dl general expression for work
If we have a chain with density of 10 Kg/m, distributed weight would be
9.8 m/s² * 10 kg = mg
Total length of th chain is 40 m, and the function of y at any time is
f(y) = (40 - y ) mg where ( 40 - y ) is te length of chain to be winded
At the beggining we have to wind 40 meters y = 0 at the end of the proccess y = 40 and there is nothing to wind then:
f(y) = mg* (40 - y )
W₁ = ∫f(y) * dy ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy
W₁ = mg [ 40*y |₀⁴⁰ - 1/2 * y² |₀⁴⁰ ⇒ W₁ = mg* [ 40*40 - 1/2 (40)² ]
W₁ = mg * [1/2] W₁ = 10*9,8* ( 800 )
W₁ = 78400 [J]
b) Now we can calculate work to do if we have a 25 block and the chain is weightless
W₂ = ∫ mg* dy ⇒ W₂ = ∫₀⁴⁰ mg*dy ⇒ W₂ = mg y |₀⁴⁰
W₂ = mg* 40 = 10*9.8* 40
W₂ = 3920 [J]
Total work
Wt = W₁ + W₂ ⇒ Wt = 78400 + 3920
Wt = 82320 [J]
The average rate of change of the function over −2 ≤ x ≤ 2 is 1/2
<h3>How to determine the average rate of change?</h3>
The function is given as:

The interval is given as:
−2 ≤ x ≤ 2
Calculate h(2) and h(-2)

h(2) = -3

h(-2) = -5
The average rate of change is then calculated as:

This gives

Evaluate
m = 1/2
Hence, the average rate of change of the function over −2 ≤ x ≤ 2 is 1/2
Read more about average rate of change at
brainly.com/question/23715190
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<u>Complete question</u>

What is the average rate of change of h over the interval −2 ≤ x ≤ 2
Answer:
3(x+7) = 3x +21
Step-by-step explanation: