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natali 33 [55]
3 years ago
13

MATH HELP PLEASE WILL GIVE BRAINLIEST

Mathematics
1 answer:
Anni [7]3 years ago
8 0
1. 10
2. 5√2 in
1. The ratio for a 30-60-90 triangle is  x:x√3:2x 
x is the shortest leg  so 2*x =2*5 = 10
2. the ratio of a 45-45-90 triangle is x:x:x√2
x is one leg  so x * √2 = 5*√2 = 5√2
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What is the remainder of x^5+2x^4+9x^3-6x^2+3x+3165 divided by x-5
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1 year ago
Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r
ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = \frac{\sum X}{n} = 21.88 ounces

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.201 ounces

            n = sample of boxes = 12

            \mu = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.796 < t_1_1 < 1.796) = 0.90  {As the critical value of t at 11 degrees of

                                                  freedom are -1.796 & 1.796 with P = 5%}  

P(-1.796 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.796) = 0.90

P( -1.796 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.796 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.796 \times {\frac{s}{\sqrt{n} } } , \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 21.88-1.796 \times {\frac{0.201}{\sqrt{12} } } , 21.88+1.796 \times {\frac{0.201}{\sqrt{12} } } ]

                                        = [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0
3 years ago
TERESA gave away 8 baseball cards and has 4 BASEBALL cards left. WRITE A subtraction problem tp show the fraction of he baseball
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Teresa gave away 8 baseball cards and has 4 left. 8 plus 4 means she originally had 12. Right now she has 4 out of her original 12 cards remaining. This gives us 4/12. We can simplify this by dividing our greatest common factors. 4 goes into both parts of our fraction, when we divide each part by 4 we end up with 1/3. Since we are unable to simplify this problem any further, this means our solution and fraction is 4/12 aka 1/3.
4 0
3 years ago
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