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xeze [42]
3 years ago
6

Ten less than three times the sum of a number and five is equal to twenty-nine. What is the number ?

Mathematics
1 answer:
kozerog [31]3 years ago
3 0
Hello!
So the following would be your equation.
3(x+5)-10= 29
Your first step would be to use the Distributive Property based upon PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction). Since we have Parenthesis, we distribute first.
3(x+5)-10=29
^ ^
——————
So, your new equation would be—
3x+15-10=29
Now, you need to combine like terms—
15-10=29
3x+5=29
——————
Therefore your new equation is—
3x+5=29.
Now you need to move the constants (5,29) to one side of the equal sign. To do this, you would use the Subtraction Property of Equality and rid the 5–
3x+5=29
-5 -5
——————
Your equation is now—
3x=24.
Finally, you need to remove the 3 from x. This means you must use the Division Property of Equality, and rid the 3.
3x=24
— —
3 3
Your solved equation is—
X=8

Hope this helped!
~KayEmQue

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A flowerbed surrounds the base of a tree. It’s enclosed by stones to form a circle that measures 25.12 feet. What is the radius
Ymorist [56]
2.83 if rounded. 2.82842712475 would be the actual.

Hope this helped!
5 0
3 years ago
The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F
Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

13y=13

y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

6 0
3 years ago
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
3 years ago
Which expression correctly represents three less than the product of a number and two increased by five? ​
daser333 [38]

Answer:

The answer is 3-n2-5

<3

5 0
3 years ago
3(-4+x)&lt;-33 I need to solve for x​
Serjik [45]

Answer:

−7

Step-by-step explanation:

7 0
3 years ago
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