It was about 17.4%
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% error=
actual value-estimated value
Then divide that by actual value
Answer:416
Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:
The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km
and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km
So add the given results above with 500 km and this will be the additional distance that plane moves through the air.
The answer would be in the unit meters.
((10√401 +10√901−500)∗1000)=416 meters
Hope this is the answer that you are looking for.
Answer:
c. The mean is the same as the average. The average is (6 * 5 + 7 * 4 + 8 * 7 + 9 * 10 + 10 * 4) / (5 + 4 + 7 + 10 + 4) = 244 / 30 = 8.133.
Answer:
148.005
Step-by-step explanation:
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Define adult and student tickets
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Let the number of adult tickets be x
Adult tickets = x
Student tickets = x + 69
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Form equation and solve for x
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x + x + 69 = 569
2x + 69 = 569 ← Combine like terms
2x = 569 - 69 ← Subtract 69 from both sides
2x = 500
x = 250 ← Divide by 2 to find x
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Find the number of adult tickets and student tickets
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Adult tickets = x = 250
Student tickets = x + 69 = 319
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Answer: Adult tickets = 250 ; Student tickets = 319
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