Maria added 45,273 and 37,687 and got the sum of 70,960. is maria's answer reasonable? explain.

A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,

katovenus [111]

Answer:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation

$X_{1}=45$ represent the number of correct answers for university degree holders

$X_{2}=57$ represent the number of correct answers for university non-degree holders

$n_{1}=373$ sample 1 selected

$n_{2}=639$ sample 2 selected

$p_{1}=\frac{45}{373}=0.121$ represent the proportion of correct answers for university degree holders

$p_{2}=\frac{57}{639}=0.0892$ represent the proportion of correct answers for university non-degree holders

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0

3 years ago

PLEASE HELP ME WITH THIS! ASAP please and thank you

galben [10]

Just plug in

4a / (2b - c)

= 4(5) / (2*4 - 6)

= 20 / 2

= 10

Answer

10

5 0

3 years ago

Read 2 more answers

here are the ingredients for making fish pie for 5 people. 180g flour,240g fish,80g butter,4 eggs, 180ml milk . Lan makes a fis

kvasek [131]

5p = 80b
3(5p) = (80b)3
15p = 240b

Lan need 240g of butter to make fish pie for 15 people.

8 0

3 years ago

Read 2 more answers

a student found the volume of a rectangular pyramid with a base area of 92 square meters and a height of 54 Meters to be 4968 cu

Naya [18.7K]

It is not correct.

The student found the volume by multiplying the base area with the height. He forgot to divide it by 3.

Formula to find the volume of the pyramid = 1/3 base area x height

volume = 1/3 x 92 x 54 = 1656 square meters

6 0

3 years ago

Read 2 more answers

a vehicle factory manufactures cars. The unit cost C (the cost in dollars to make each car) depends on the number of cars made.

timofeeve [1]

Answer:

8,567

Step-by-step explanation:

Given the cost function expressed as C(x)=0.7x^2- 462 x + 84,797

To get the minimum vaklue of the function, we need to get the value of x first.

At minimum value, x = -b/2a

From the equation, a = 0.7 and b = -462

x = -(-462)/2(0.7)

x = 462/1.4

x = 330

To get the minimum cost function, we will substitute x = 330 into the function C(x)

C(x)=0.7x^2- 462 x + 84,797

C(330)=0.7(330)^2- 462 (330)+ 84,797

C(330)= 76230- 152460+ 84,797

C(330) = 8,567

Hence the minimum unit cost is 8,567

7 0

3 years ago