Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
we know that
EB=ED+DB
ED=DB -----> given problem
Substitute the given values and solve for x




<em>Find the value of ED</em>

substitute the value of x

<em>Find the value of DB</em>
Remember that
ED=DB
therefore

<em>Find the value of EB</em>
EB=ED+DB

Answer:
This sum is the sum of an arithmetic sequence. There is a formula for the sum of an arithmetic sequence which can be looked up or derived by a variety of means.
A nice approach for this sequence is the following. Notice that the sum of first and last number in the sequence is the same as the sum of the second and second last, and also the same as the sum of the third and third last, and so on.
There are n of these pairs. So the desired sum is n x (first number + last number). But the first number is 1 and the last on is 2n. Thus the desired sum is n(1 + 2n).
Hope this helps!!
Mark Brainleast!!!!!!!!!!!
Answer:
No, none of the number need to be 48 for the mean to be 48. To get a mean, you add up all the number and divide it by the amount of numbers.
Example:
the mean of 10, 79, 42, 88, 19, and 50 is 48, but the actual number 48 was not part of the set.
10 + 79 + 42 + 88 + 19 + 50 = 288
288 ÷ 6 = 48
Answer:
Sam has $900 more money. In total he now has $905.