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Lostsunrise [7]
3 years ago
6

A train stops at Atlanta, then at Bayville, and then at Colleyville. The

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
3 0

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete as what is required of the question is not stated.</em>

<em>However, since the question is only limited to distance, a likely question could be to calculate the distance from Bayville to Colleyville.</em>

Represent the distance from Atlanta to Colleyville with AC

Represent the distance from Atlanta to Bayville with AB

Represent the distance from Bayville to Colleyville with BC

So, we have that:

AC = 25.5\ miles

AB = 10\frac{2}{3}\ miles

The relationship between AB, AC and BC is:

AC = AB + BC

Make BC the subject of formula:

BC = AC - AB

BC = 25.5 - 10\frac{2}{3}

Convert fraction to decimal

BC = 25.5 - 10.7

BC = 14.8

<em>Hence, the distance from Bayville to Colleyville is 14.8 miles</em>

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Below are the jersey numbers of 11 players randomly selected from a football team. Find the​ range, variance, and standard devia
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Answer:

Option(A) is correct

Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

Step-by-step explanation:

The given data set in the question are ;33, 29, 97, 56, 26, 78, 83, 74, 65, 47, 58

the range can be determined by finding the highest value and subtract it to the lowest value. In this case the values are:

Highest = 97

Lowest = 71

Range = highest value - Minimum value

Range = 97 - 26 = 71

Range= 71

mean of the data is the summation of all the numbers in the data set divided by the number of given samples.

Mean = (33 + 29 + 97 + 56+ 26 + 78 + 83 74+ 65 + 47 + 58)/11

= 647/11

Mean value =58.7

Now to find the variance of the data set by using below formular

σ²=[ (xᵢ -mean)²]/n-1

[(33-58.7)² +(29-58.7)²+( 97-58.7)²+( 56-58.7)²+( 26 -58.7)²+(78-58.7)²+( 83 -58.7)²+(74-58.7)²+( 65-58.7)²+( 47 -58.7)²+(58 -58.7)²]/10

Variance=546

Now, we will calculate standard deviation by taking square root over variance

σ =√(variance)

σ =√(546)

Standard deviation= 23.4

Hence, the range is 71 ,variance is 546 and standard deviation is 23.4 therefore,

Option A is the answer that is Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

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