By taking the quotients between the areas, we see that:
<h3>
How to find the probabilities?</h3>
First we need to find the areas of the 3 shapes.
For the triangle, the area is:
T = 3*5/2 = 7.5
For the blue square, the area is:
S = 3*3 = 9
For the rectangle, the area is:
R = 10*6 = 60
Now, what is the probability that a random point lies on the triangle or in the square?
It is equal to the quotient between the areas of the two shapes and the total area of the rectangle, this is:
P= (7.5 + 9)/60 = 0.275
b) The area of the rectangle that is not the square is:
A = 60 - 9 = 51
Then the probability of not landing on the square is:
P' = 51/60 = 0.85
If you want to learn more about probability:
brainly.com/question/25870256
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Y-4=2/-3(x-6) I believe that’s the answer hope this helped
Answer: B
If you need help with anything else, reply to this!
Answer:
y(x) = 1 - x
Step-by-step explanation:
Given the two parametric equations:
---(1)
----(2)
We can add eq (1) and eq (2) and consider the trigonometric identity:

so,

in other way we can express this like:
[tex] y(x)=1-x [tex].
Step-by-step explanation:
6x²-13x+6
= 6x²-9x-4x+6
= 3x(2x-3)-2(2x+3)
= (2x-3)(3x-2)
Therefore, the roots are x=3/2 and x=2/3