The question ask to find the rate of change of the distance from the paticle to the origin at this instant where as a particle is moving along the curve y = 5sqrt(5x+4) and base on my calculation, I came up with an answer of 254/sqrt(226). I hope you are satisfied with my answer and feel free to ask for more
Answer:
x=48
Step-by-step explanation:
x-3 15
------------ = ----------
6 2
We can use cross products to solve this problem
(x-3) *2 = 6*15
Distribute
2x-6 = 90
Add 6 to each side
2x-6+6 = 90+6
2x=96
Divide by 2
2x/2 = 96/2
x = 48
The equation is:
[e^x] [e^(2x)] = 4
1) Applying property of multiplication of powers wiith same base =>
e ^ (x + 2x) = 4
=> e ^ (3x) = 4
2) Applying logarigth properties
3x = ln(4)
=> x = ln(4) / 3 ≈ 1.38629 / 3 ≈ 0.4621
Answer: x = ln(4) / 3 ≈ 0.4621
<u>Answer:</u>
A. y = -2 - cos(x-π)
<u>Explanation:</u>
<u>The general form of the trig equation is:</u>
y = A sin (Bx + C) + D
where:
A is the amplitude
is the period
is the phase shift
D is the vertical shift
<u>Now, let's check the choices:</u>
<u>A. y = -2 - cos(x-π)</u>

Therefore, the function has a phase shift of π
<u>B. y = 3 cos(4x)</u>

Therefore, the function has no phase shift
<u>C. y = tan(2x)</u>

Therefore, the function has no phase shift
<u>D. y = 1 + sin(x)</u>

Therefore, the function has no phase shift
<u>Based on the above,</u> the correct answer is A
Hope this helps :)