The trifecta at most racetracks consists of selecting the first-, second-, and third-place finishers in a particular race in t
1 answer:
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Answer:
Step-by-step explanation:
[ (x + 7) / 6 ] − [ (x + 5) / (x + 3) ]
First, we must find the common denominator. In this case, that's 6 (x+3). Multiply the first fraction by (x+3)/(x+3) and the second fraction by 6/6.
[ (x + 7)(x + 3) / (6 (x + 3)) ] − [ 6 (x + 5) / (6 (x + 3)) ]
Now distribute the numerators:
[ (x² + 10x + 21) / (6 (x + 3)) ] − [ (6x + 30) / (6 (x + 3)) ]
Now we combine the fractions:
((x² + 10x + 21) − (6x + 30)) / (6 (x + 3))
(x² + 10x + 21 − 6x − 30) / (6 (x + 3))
(x² + 4x − 9) / (6 (x + 3))
So the simplified form is:
Answer:
Step-by-step explanation:
Given:
Number of questions (N) = 16
Number of easy questions (E) = 8
Number of medium-hard questions (M) = 5
Number of hard questions (H) = 3
Now, the probability of getting the first question as easy question is given as:
Now, probability of getting the second question as easy question is given as:
Now, probability that the first two contestants will get easy questions is given by the product of . So,
Therefore, the probability that the first two contestants will get easy questions is