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natima [27]
3 years ago
8

What is the simplified form of the quantity of x plus 7, all over the quantity of 6 − the quantity of x plus 5, all over the qua

ntity of x plus 3?
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

Step-by-step explanation:

[ (x + 7) / 6 ] − [ (x + 5) / (x + 3) ]

First, we must find the common denominator.  In this case, that's 6 (x+3).  Multiply the first fraction by (x+3)/(x+3) and the second fraction by 6/6.

[ (x + 7)(x + 3) / (6 (x + 3)) ] − [ 6 (x + 5) / (6 (x + 3)) ]

Now distribute the numerators:

[ (x² + 10x + 21) / (6 (x + 3)) ] − [ (6x + 30) / (6 (x + 3)) ]

Now we combine the fractions:

((x² + 10x + 21) − (6x + 30)) / (6 (x + 3))

(x² + 10x + 21 − 6x − 30) / (6 (x + 3))

(x² + 4x − 9) / (6 (x + 3))

So the simplified form is:

\frac{x^{2} + 4x - 9}{6 (x + 3)}

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A jar contains 4 blue, 11 pink, 5 red, and 6 orange jellybeans. Once is selected, replaced, then another is selected. Find P(blu
faltersainse [42]

Answer:

P(blue then red)=5/169

Step-by-step explanation:

the probability of picking the blue is 4/26 it's replaced so the total jellybeans doesn't change therefore the sample space doesn't change. the probability of picking a red is 5/26

to find the probability of picking them in that order, you multiply the two together

(4/26)x(5/26)=20/676

reducing that we get:

P(blue then red)=5/169

4 0
2 years ago
Marcy purchases a total of 12 adult, child, and senior tickets for an art museum tour. Adult tickets are $5 each, child tickets
Kruka [31]

Answer:

A: The solution to this system is no viable because it results in fractional values of tickets

Step-by-step explanation:

Let number of adult, child, and senior tickets be x, y and z respectively.

Thus;

x + y + z = 12 - - - (eq 1)

she purchases 4 more child tickets than senior tickets.

Thus, y = z + 4

Thus:

x + (z + 4) + z = 12

x + 2z + 4 = 12

x + 2z = 8 - - - (eq 2)

Also, We are told that Adult tickets are $5 each, child tickets are $2 each, and senior tickets are $4 each. She spends a total of $38,

Thus;

5x + 2(z + 4) + 4z = 38

5x + 2z + 8 + 4z = 38

5x + 6z + 8 = 38

5x + 6z = 38 - 8

5x + 6z = 30

Divide through by 5 to get;

x + (6/5)z = 6 - - - (eq 3)

Subtract eq 2 from eq 1 to get;

2z - (6/5)z = 8 - 6

2z - (6/5)z = 2

Multiply through by 5 to get;

10z - 6z = 10

4z = 10

z = 2½

It's not possible to have a fractional value of a ticket and thus we can say that the solution is not viable.

6 0
3 years ago
Select the equations that are equivalent to the equation y – 2 = 3(x + 6). Select all that apply.
amm1812
The correct answer for the exercise shown above is the first option and the las option, which are:

 <span>y = 3x + 20
 3x - y = -20
</span>
 The explanation is shown below:

 1. You have the folllowing expression given in the problem above:

 y-2=3(x+6)

 2. If you solve it for y, you have:

 y-2=3x+18
 y=3x+18+2
 y=3x+20

 3. And if you move the variables to the left member, you have:

 3x-y=-20

 Therefore, as you can see, the correct answer are the options mentioned above.

 
3 0
4 years ago
Please Asap :))))
kicyunya [14]

Answer:

d> -7

Step-by-step explanation:

If his goal is to have more by the end of the month and he did, D would be greater (I also had this question and got it correct.)

7 0
3 years ago
John had $5. Marcus had $10. Each boy spent 0.1 of his money.
Lera25 [3.4K]
The answer is c 
hope i helped 

7 0
3 years ago
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