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Aloiza [94]
3 years ago
13

What is the length of MN¯¯¯¯¯¯¯ ? Round to the nearest tenth of a unit. Enter your answer in the box. units Line segment on a co

ordinate grid. Segment begins at point M whose coordinates are begin ordered pair two comma negative two end ordered pair and ends at point N whose coordinates are begin ordered pair eight comma four end ordered pair. Link to the piccture of the problem:https://static.k12.com/nextgen_media/assets/1578500-MS_IMC-150122-130504.jpg
Mathematics
2 answers:
notka56 [123]3 years ago
6 0
I'm actually doing this quiz right now, so I'll let you know what the answer is.
velikii [3]3 years ago
5 0

Answer:

it's 8.5 Because I did the quiz too.

Step-by-step explanation:

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Find the mean absolute deviation for the set below s equals 65 , 90, 85, 70, 70, 95, 55
ddd [48]

75.7 I think that is the answer

5 0
3 years ago
The growth of a strain of bacteria can be modeled by the function graphed, where the x-values are the time in seconds and the y-
Andrew [12]

There are (A) 2.7 bacterias initially.

<h3>What is a function?</h3>
  • A function is an expression that establishes the relationship between the dependent and independent variables.
  • A function from a set X to a set Y allocates exactly one element of Y to each element of X.
  • The set X is known as the function's domain, while the set Y is known as the function's codomain.
  • Originally, functions were the idealization of how a variable quantity depends on another quantity.

To find the number of bacteria:

  • The graph shows that the function follows an exponential curve, and the starting point is at ( 0,2.7 ).
  • The starting number of bacteria is then 2.7.

Therefore, there are (A) 2.7 bacterias initially.

Know more about functions here:

brainly.com/question/25638609

#SPJ4

The correct question is given below:
The growth of a strain of bacteria can be modeled by

the function graphed, where the x-values are the time

in seconds and the y-values are the number of

bacteria. How many bacteria are there initially?

(A) 2.7

(B) 2.8

(C) 4

3 0
1 year ago
All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

5 0
3 years ago
Plot the following points on the graph paper:
mote1985 [20]

Answer:

check the screenshot I attached:

6 0
2 years ago
I will give brainiest if random will report please include the expression in answer
Mandarinka [93]

(m - 1/2) + 25

Plz give me brainlest

7 0
2 years ago
Read 2 more answers
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