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Harlamova29_29 [7]
3 years ago
15

Grady marks down some $4.09 pens to $3.59 for a week and then marks them back up to $4.09. Find the percent of increase and the

percent of decrease to the nearest tenth. Are the percents of change the same for both price changes? If not, which is a greater change
Mathematics
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

Percentage decrease ( from $4.09 to $3.59) is 0.1% ( Rounded to nearest tenth)

Percentage increase (from $3.59 to 4.09) is 0.1% ( Rounded to nearest tenth)

Percentages are not same for the both price changes. As we can see from the calculations percentage change from $3.59 to $4.09 is higher.

Step-by-step explanation:

$4.09 has been changed to $3.59.

Percent change = [(Value after  - Value before) / Value before]*100

                          =\frac{3.59-4.09}{4.09}*100%

                          =\frac{-0.5}{4.09}*100%

                          =-0.122249%

                           =-0.1% ( Rounded to nearest tenth)

Percentage decrease is 0.1% ( Rounded to nearest tenth)

Now lets calculate the percentage change from $3.59 to $4.09.

Percent change = [(Value after  - Value before) / Value before]*100

                          =\frac{4.09-3.59}{3.59}*100%

                          =\frac{0.5}{3.59}*100%

                          =0.13927%

                           =0.1% ( Rounded to nearest tenth)

Percentage increase is 0.1% ( Rounded to nearest tenth)

Percentages are not same for the both price changes. As we can see from the calculations percentage change from $3.59 to $4.09 is higher.

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Answer:

  x = 5

Step-by-step explanation:

The equality of bases property says powers of the same base will be equal if and only if the powers are equal. This property is used to solve exponential equations.

<h3>Application</h3>

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<em>Additional comment</em>

Equating the exponents is fully equivalent to taking the logarithm of both sides of the equation, to that base.

  \log_2(2^x)=\log_2(2^5)\ \Longrightarrow\ x=5

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