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pshichka [43]
3 years ago
5

When a government transfers the rights and obligations of an asset to another legally separate governmental or private sector en

tity, the transaction is referred to as:_______
a. A sale-leaseback agreement.
b. A capital lease.
c. An operating lease.
d. A service concession arrangement.
Business
1 answer:
Mamont248 [21]3 years ago
4 0

Answer: A service concession arrangement (D)

Explanation:

A service concession arrangement is an agreement whereby the government contracts with a private enterprise in order to operate, develop and maintain an infrastructural facility such as a tunnel, bridge, road, hospital, airport or prison. The government regulates and controls the kind of services the operator must provide, to whom the services are provided and at the price the services will be provided.

Concession agreements can also be between a non-governmental owner and a concessionaire, whereby the non-governmental owner gives the operator the exclusive rights to use and maintain the business for a stipulated period of time under specified conditions.

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entrepreneurs

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Dixie Bank offers a certificate of deposit with an option to select your own investment period. Jonathan has ​$8 comma 000 for h
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Answer:

A = P * (1 + r/n)^nt. Where A = Maturity amount = ? P = Principal amount = $8,000, r = Rate of interest = 6%, n = Number of compounding per year = 1, t = Number of year

a. t = 2

A = $8,000 * (1 + 0.06/1)^1*2

A = $8,000 * (1.06)^2

A = $8,000 * 1.1236

A = $8,988.80

b. t = 6

A = $8,000 * (1 + 0.06/1)^1*6

A = $8,000 * (1.06)^6

A = $8,000 * 1.418519

A = 11348.152

A = $11,348.15

c. t = 10

A = $8,000 * (1 + 0.06/1)^1*10

A = $8,000 * (1.06)^10

A = $8,000 * 1.7908477

A = 14326.7816

A = $14,326.78

d. t = 15

A = $8,000 * (1 + 0.06/1)^1*15

A = $8,000 * (1.06)^15

A = $8,000 * 2.3965581931

A = 19172.4655448

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Answer:  The probabilities of winning a contract are

P(A) = \frac{28}{36}  

P(B) = \frac{7}{36}  

P(C) = \frac{1}{36}


Let the Probability of C winning the contract - P(C) be 'X'

Then,

Probability of B winning the contract - P(B) will be '7X'     and

Probability of A winning the contract - P(A) will be \mathbf{P(A) = 4 * P(B) = 4*7X = 28X}

Since the total of all the probabilities is 1,

\mathbf{P(A) + P(B) + P(C) =1}

\mathbf{28X + 7X + X =1}

\mathbf{36X =1}

\mathbf{X =\frac{1}{36}}

So,

P(A) = \frac{28}{36}

P(B) = \frac{7}{36}

P(C) = \frac{1}{36}

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3 years ago
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