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jeka94
3 years ago
13

An adjusting entry was made on year-end December 31 to accrue salary expense of $3,000. Assuming the company does not prepare re

versing entries, which of the following entries would be prepared to record the $6,600 payment of salaries in January of the following year?
a. Salaries Expenses 4,600
Cash 4,600
b. Salaries Payable 4,600
Cash 4,600
c. Salaries Payable 2,000
Cash 2,000
d. Salaries Expenses 2,000
Salaries Payable 2,000
Business
1 answer:
wel3 years ago
5 0

Answer:

Dr Salaries Payable $3000

Dr Salaries Expense $3600

Cr Cash $6600

Explanation:

Preparation of the entries to record the $6600 payment of salaries in January of the following year.

Based on the information given Appropriate journal entries to record the $6600 payment of salaries in January of the following year will be:

Dr Salaries Payable $3000

Dr Salaries Expense $3600

($6600-$3000)

Cr Cash $6600

(To record payment of salaries)

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  1. The particular property possessed by both sisters is Intellectual property.
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  3. Kanchan's property belongs to the industrial class property.

<h3>Intellectual property</h3>

This text about the sisters Minakshi and Kanchal refers to the particular property called <u>Intellectual property, </u>which is a property that includes the creations of the human intellect, everything that was created by the person's mind.

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2 years ago
A company offers ID theft protection using leads obtained from client banks. Three employees work 40 hours a week on the leads,
sertanlavr [38]

Answer:

Ans. Multifactor productivity (per dollar of input) = 1.9385

Explanation:

Hi, in order to find the multifactor productivity (per dollar of input) , we have to use the following equation.

MP=\frac{GeneratedFees}{Labour+Materials+Overhead}

So let´s find out the amount of each of the items in the equation.

Generated fees.

There are 3 employees and they find 3,000 potential leads every week, but only 4% actually sign up fo that $70 fee. That is:

3(employees)*3,000(leads)*0.04(ratio Effective leads)*$70(fee)=25,200

So the output or  generated fees are 25,200.

Input.

Our inputs are: Labour+Materials and Overhead, materials are $1,000, Overhead is $9,000 and Labour is 3 emplyees, working 40 hours at $25 per hour per employee, that is: 3*40*24= $3,000.

Now, we have all we need to use the first equation.

MP=\frac{25,200}{3,000+1,000+9,000}= 1,9385

Best of luck

8 0
3 years ago
The residents of cities A, B, C, D and E consume wi-fi routers, with consumption in each city is 150 routers (see the map below)
natta225 [31]

Answer:

a. The production process shows that the more the quantity produced, the less the average cost of production.  It proves that there are advantages arising from economies of scale.

AC with Q = 150 = $10 ($1,500/150) and

AC with Q = 750 = $2 ($1,500/750)

b. The optimal arrangement is (centralized production) to produce the 750 routers at city C and ship to the 4 other cities.

c. AC with Q = 150 = $10 (14000/(150+1250) and

AC with Q = 750 = $7 (14000/(750+1250)

d. The cost-minimizing arrangement of production in this case is decentralized production.

e. The average cost of producing 150 units at the various cities has remained unchanged while the average cost of producing the 750 units at city C has increased from $2 to $7.

f. Suppose now production costs are those given in part (a) but let shipping cost per router be given by t (in the preceding discussion, we had t = 6, now we assume we don’t know the cost of shipping).

The value of t that would make the two arrangements for production (centralized versus separate factories) equivalent in terms of cost is:

t = $10 per router

Therefore, centralized production cost will be equal to $7,500 ($1,500 + ($10 * 600), and decentralized production cost will remain at $7,500 (750 * $10).

Explanation:

a) Data and Calculations:

Cities with consumers of wi-fi routers = A, B, C, D and E

Demand for routers by each city = 150

Total number of routers required = 750 (150 * 5)

b) Suppose the average cost of producing a router is AC (Q) = 1500/Q, where Q is the number of routers produced in a factory:

Therefore AC with Q = 150 = $10 ($1,500/150) and

AC with Q = 750 = $2 ($1,500/750)

Cost of Production of routers in city C:

cost of producing 750 routers at $2 per router = $1,500

Shipping cost of 600 routers to 4 cities at $6 per router = $3,600

Total cost of producing at city C = $5,100 ($1,500 + $3,600)

Total cost of producing 750 routers at 5 cities = $7,500 ($1,500/150 * 750)

c) Suppose the average cost of producing a router is AC = 14000/(Q+1250):

Therefore, AC with Q = 150 = $10 (14000/(150+1250) and

AC with Q = 750 = $7 (14000/(750+1250)

Cost of Production of routers in city C:

cost of producing 750 routers at $7 per router = $5,250

Shipping cost of 600 routers to 4 cities at $6 per router = $3,600

Total cost of producing at city C = $8,850 ($5,250 + $3,600)

Total cost of producing 750 routers at 5 cities = $7,500 ($1,500/150 * 750)

d) $7,500 = $1,500 + tQ

where Q = 600 (150 * 4)

Therefore, $7,500 - $1,500 = t600

simplifying

t600 = $6,000

t = $6,000/600 = $10

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