-4.5,1.5),(0,-2),(-1.2,0)
The smallest number of students in the class is the smallest number that is divisible by 2, 3, and 4. You need the least common multiple of 2, 3, and 4.
This is like finding the least common denominator.
Find the prime factors of the three numbers:
2 = 2
3 = 3
4 = 2^2
To find the LCM you need common factors, and not common factors with the larger exponent.
Now single factor is common to all numbers.
There is 2 and 2^2, so use 2^2 since it has the larger exponent.
There is also a 3, so use the 3.
LCM = 2^2 * 3 = 4 * 3 = 12
Mr. Carson's class may have 12 students. 12 is the smallest number of students it can have.
Answer:
The mistake was made in the second step when going from 3x - 2(3x-4) = 13 to 3x - 6x - 8 = 13.
The mistake was in the multiplication of -2(3x-4). The error is that the negative sign was not distributed to both the 3x and the -4.
-2 times 3x is -6x and -2 times -4 is positive 8
Step-by-step explanation:
y = 3x - 4
3x - 2y = 13
------------------------
3x - 2(3x - 4) = 13
3x - 6x + 8 = 13
-3x + 8 = 13
-3x = 5
x = -5/3
y = 3(-5/3) - 4
y = -5 - 4
y = -9
Solution: x = -5/3 and y = -9
Answer:
Uhh...how do you want me to answer this question??? Let me know so I can help ya out.
Step-by-step explanation:
