Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by

In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
Marked price = 200 + 40% of 200 = 200 * 0.4*200 = 200 + 80 = $280
price after 25% discount = 280 - 0.25*280
can you work that out?
Answer:
1. 100cm
2. 300.1cm
3. 200cm
4. 400cm
5. 299.00cm
Step-by-step explanation:
300-200=100
300+0.01=301
300-100=200
300+100=400
300-0.01=299.99
-25+(-12)=-37
14-(-20)=34
-4+(-10)=-14
Answer:
21
Step-by-step explanation:
27÷3 is 9 and 21÷3 is 7