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3 years ago

how do you solve 2x-10=44+8× and -7x-2=24-9x and 27-11x=x-33 and 21x+6=17x-26 and 11x=8x-6 and -x-29=13+2x

1 answer:

7 0

2x-10=44+8x
subtract 2x from each side
8x-2x=6x
now we have -10=44+6x
subtract 44 from both sides
-10-44=-54
now we have -54=6x
divide both sides by 6
-54/6=-9
so x=-9

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Order theses numbers least to greastest 3.18 3.1 3.108 2.1952

mel-nik [20]

Answer:

2.1952, 3.1, 3.108. 3.18

Step-by-step explanation:

Look at the ones place first, ignoring the decimal. The number is 2.1952. It is the lowest value among all the numbers. The other numbers are 3.18, 3.1, and 3.108. If we want to find the lowest among these three, we will have to minus one number from another, and if we see the result is positive, the first number in the calculation will be greater. So, 3.108-3.1= 0.008, which is positive. That means 3.108> 3.1. Again, 3.18-3.108= 0.72, which is also positive. So, 3.18> 3.108. So, the sequence will be 2.1952< 3.1 < 3.108 < 3.18

6 0

4 years ago

A researcher is interested in looking at a new type of insulin that can treat diabetics with high fasting glucose levels. Suppos

Makovka662 [10]

Answer:

The sample size should be at least 79.

Step-by-step explanation:

Let Y be be the resting glocose level of a member of the population chosen randomly, then Y is a random variable with unkown mean λ and Standard deviation σ = 27.

Let X be the sample mean of a sample of lenght n. X has the same mean as Y and the standard deviation is $\sigma = \frac{27}{\sqrt{n}} .$

If n is reasonable high, the Central Limit Theorem states that X has distribution approximately Normal, with mean λ and Standard deviation $sigma = \frac{27}{\sqrt{n}} .$

If we standarize X, we get a random variable W

$W = \frac{X-\lambda}{\frac{27}{\sqrt{n}}} \simeq N(0,1)$

The values of W are tabulated and can be found on the attached file. We want a 95% confidence interval, so we want Z such that

P(-Z < w < Z) = 0.95

Using the symmetry of the normal density function, we get that

P(W < Z) = 0.975

If we look at the table, we will find that Z = 1.96, therefore we have

$P(-1.64 < \frac{X-\lambda}{\frac{27}{\sqrt{n}}} < 1.64) = 0.95$

Equivalently,

$0.95 = P(-1.64*\frac{27}{\sqrt{n}} < X- \lambda < 1.64*\frac{27}{\sqrt{n}})$

Taking out the X and the sign, after reverting the inequalities, we obtain

$P(X -1.64*\frac{27}{\sqrt{n}} < \lambda < X +1.64*\frac{27}{\sqrt{n}}) = 0.95$

Thus, a confidence interval with 95% confidence is

$CI = [ X-1.64*\frac{27}{\sqrt{n}}, X+1.64*\frac{27}{\sqrt{n}}]$

The (absolute) margin of error of this interval is $1.64*\frac{27}{\sqrt{n}} ,$ we want that number to be at most 5, so we take n such that

$1.64*\frac{27}{\sqrt{n}} = 5 \, \rightarrow \frac{1}{\sqrt{n}} = \frac{5}{1.64*27} \, \rightarrow \sqrt{n} = 8.85 \, \rightarrow n = 78.42$

We take n = 79. I hope that works for you!

Download pdf

4 0

3 years ago

3,893 : 4 Quotient: Remainder:

Molodets [167]

Answer:

Step-by-step explanation:

Quotient = 973

Remainder = 1

5 0

3 years ago

In a particular week a man receives 909.50 but 229.50 was for a overtime. If he works a basic week of 40 hours and overtime is p

Airida [17]

Total salary = 909.50
Out of this, overtime salary was = 229.50

Normal salary for 40 hours was = 909.50 - 229.50 = 680

Hourly rate = 680/40 = 17

Overtime is time and half = 17 + 17/2 = 17 + 8.5 = 25.5

Number of overtime hours = 229.50/25.5 = 9 hours

8 0

3 years ago

mash [69]

Answer:

Step-by-step explanation:

Because you left one pence then it is 9-1=8

3 0

4 years ago

Read 2 more answers