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lakkis [162]
3 years ago
15

Compare the functions below: f(x) = −3 sin(x − π) + 2

Mathematics
2 answers:
Bas_tet [7]3 years ago
4 0
Given:
f(x) = - 3sin(x - π) + 2
h(x) = (x + 7)² - 1

g(x):
x:       0   1   2   3   4    5   6   
g(x):   8  3   0  -1    0   3   8   

For the range 0 ≤ x ≤ 6,
(a) f(x) takes a minimum value of -3 + 2 = -1, because the minimum value
     for the sine function is -1.
(b) g(x) takes a minimum value of -1 according to the given table.
(c) h(x) takes a minimum value of 7^2 - 1 = 48 when x = 0.

A graph of f(x) and g(x) confirms the conclusions.

Answer: Both f(x) and g(x) have minimum values of -1.


Kitty [74]3 years ago
4 0

Answer: f(x)

Step-by-step explanation:

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Please help! This assignment is due soon! (In The photo)
eimsori [14]

Answer

Elena must have substracted 1/2x from both sides of the equation.

Lin must have multiplied both sides of the equation by 2

Explanation

The equation given is

\frac{1}{2}x+3=\frac{7}{2}x+5

For Elena to have arrived at

3=\frac{7}{2}x-\frac{1}{2}x+5

Then Elena must have substracted 1/2x from both sides of the equation.

That is;

\begin{gathered} \frac{1}{2}x+3=\frac{7}{2}x+5 \\ \text{Substracting }\frac{1}{2}x\text{ from both sides of the equation will give Elena first step} \\ \frac{1}{2}x+3-\frac{1}{2}x=\frac{7}{2}x+5-\frac{1}{2}x \\ 3=\frac{7}{2}x-\frac{1}{2}x+5 \end{gathered}

For Lin to have arrived at

x+6=7x+10

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\begin{gathered} \frac{1}{2}x+3=\frac{7}{2}x+5 \\ \text{Multiply both sides of the equation by the lowest common mutiple } \\ \text{of the denominator which is 2.} \\ \frac{1}{2}x(2)+3(2)=\frac{7}{2}x(2)+5(2) \\ x+6=7x+10 \end{gathered}

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1 year ago
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