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3 years ago

Which angles intercept a 20 degree arc in a circle? Select all that apply.

Mathematics

1 answer:

kobusy [5.1K]3 years ago

3 0

Answer:

B and D

Step-by-step explanation:

A 20 degree intercepted arc will correspond with two angles: the inscribed angle and the central angle.

The central angle always has the same degree measure as the intercepted arc, so we want a central angle with degree 20. So, that's B.

The inscribed angle is the angle whose vertex is on the circle, not the center. This angle always has half the measure of the intercepted arc, so we want an angle with degree 20/2 = 10. So, that's D.

Thus, the answers are B and D.

Hope this helps!

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1. La asistencia a un juego de béisbol profesional fue de 4500 personas y el dinero

Elena-2011 [213]

Resolviendo un sistema de ecuaciones veremos que se vendieron 900 boletos de $15 y 3600 boletos de $10.

<h3> ¿Cuántos boletos de cada tipo se vendieron?</h3>

Primero definamos las variables:

x = número de bolteos de $10 vendidos.
y = número de bolteos de $15 vendidos.

Sabemos que se vendieron 4500 boletos, entonces:

x + y = 4500

Y se recaudo un total de $49,500, entonces:

x*$10 + y*$15 = $49,500

Entonces tenemos un sistema de ecuaciones:

Para resolver esto, primero debemos aislar una de las variables en la primer ecuación, voy a aislar x:

x = 4500 - y

Ahora reemplazamos esto en la otra ecuación:

(4,500 - y)*$10 + y*$15 = $49,500

Ahora debemos resolver estoy para y.

$45,000 - y*$10 + y*$15 = $49,500

y*$5 = $49,500 - $45,000 = $4,500

y = ( $4,500)/$5 = 900

Entonces:

x = 4500 - 900 = 3600

Se vendieron 900 boletos de $15 y 3600 boletos de $10.

Sí quieres aprender más sobre sistemas de ecuaciones:

brainly.com/question/13729904

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2 years ago

A cone of radius 10 cm and height 16 cm is divided into two parts by a plane through the midpoint of its

bazaltina [42]

Answer:

The ratio of their volumes (the top to bottom half) is 1/7

Step-by-step explanation:

The given parameters are;

The radius, r, of the cone = 10 cm

The height of the cone = 16 cm

The point at which the cone is divided = The midpoint of the its axis and parallel to its base

The ratio of the of the volume of the two parts is given as follows;

The volume, V of the entire cone = 1/3 × Base area (π·r²) × Height, h

Therefore;

V = 1/3 × π × 10² × 16 =1600·π/3 = 1675.52 cm³

The height at which the cone is divided = 16/2 = 8 cm

The height, h₁ of the uppermost divided cone = 8 cm

The ratio of the radius to the height of the cone = 10/16 = 5/8

The radius r₁, of the uppermost divided cone = The height of the uppermost divided cone × The ratio of the radius to the height of the cone

∴ r₁ = 8 × 5/8 = 5 cm

The volume, V₁, of the uppermost divided cone = 1/3 × (π·r₁²) × h₁

∴ V₁ = 1/3 × π × 5² × 8 = 200·π/3 = 209.44 cm³

Which gives;

The volume of the lower cone, V₂ = V - V₁

V₂ = 1675.52 cm³ - 209.44 cm³ = 1400·π/3 = 1466.1 cm³

The ratio of their volumes V₁ : V₂ = V₁/V₂ = (200·π/3)/(1400·π/3) = 209.44/1466.1 = 1/7.

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