The sum of polynomials involves adding the polynomials
The other polynomial is ![y^3 -y^2+ 4y - 1](https://tex.z-dn.net/?f=y%5E3%20-y%5E2%2B%204y%20-%201)
The sum of the polynomials is given as:
![Sum = y^3 + 3y^2 + 4y - 4](https://tex.z-dn.net/?f=Sum%20%3D%20y%5E3%20%2B%203y%5E2%20%2B%204y%20-%204)
One of the polynomials is given as:
![P = 4y^2 - 3](https://tex.z-dn.net/?f=P%20%3D%204y%5E2%20-%203)
Represent the other polynomial with Q.
So, we have:
![P +Q =Sum](https://tex.z-dn.net/?f=P%20%2BQ%20%3DSum)
Substitute the expressions for P and Sum
![4y^2 - 3 +Q =y^3 + 3y^2 + 4y - 4](https://tex.z-dn.net/?f=4y%5E2%20-%203%20%2BQ%20%3Dy%5E3%20%2B%203y%5E2%20%2B%204y%20-%204)
Make Q the subject
![Q =y^3 + 3y^2 -4y^2+ 4y - 4 +3](https://tex.z-dn.net/?f=Q%20%3Dy%5E3%20%2B%203y%5E2%20-4y%5E2%2B%204y%20-%204%20%2B3)
Evaluate like terms
![Q =y^3 -y^2+ 4y - 1](https://tex.z-dn.net/?f=Q%20%3Dy%5E3%20-y%5E2%2B%204y%20-%201)
Hence, the other polynomial is ![y^3 -y^2+ 4y - 1](https://tex.z-dn.net/?f=y%5E3%20-y%5E2%2B%204y%20-%201)
Read more about polynomials at:
brainly.com/question/1487158
Mean is adding all the goals together then dividing by how many games there were so it’d be 48/8 = 6
Answer: isn't it 21 then?
Step-by-step explanation:
kinda bad at math haha