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Snowcat [4.5K]
3 years ago
14

In how many ways can three married couples attending a concert be seated in a row of six seats if

Mathematics
1 answer:
OleMash [197]3 years ago
3 0
 i think it would be 30 ways 

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Plz help me i need 100%
leva [86]
The answer is D.) 5/7
7 0
2 years ago
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Tracy Tomillo is a disc jockey at WGMH. Her annual salary is $52,750. What is her monthly salary?
Juli2301 [7.4K]

Answer:

Her monthly salary is $4395.83

Step-by-step explanation:

Annual = 12 months

12 months = $52 750

1 month = $52 750 ÷ 12

= $4395.83(2d.p)

Monthly = $4395.83

(Correct me if i am wrong)

7 0
3 years ago
Multiply.
Nady [450]

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Explanation:</h2>

Here we have the following expression:

3\sqrt{22}\sqrt{58}\sqrt{18}

So we need to simplify that radical expression. By property of radicals we know that:

\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}

So:

3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}

The prime factorization of 22968 is:

22968=2^3\cdot 3^2\cdot11\cdot 29

Hence:

3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}

By property:

\sqrt[n]{a^n}=a

So:

3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}

Finally:

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

3 0
3 years ago
Solve the inequality: -6w - 18 ≥ 36
astra-53 [7]
The answer to the question

7 0
3 years ago
A shopper payed $530 for an item marked $500 what is the percent of the sales tax
motikmotik

Answer:

First find the amount of tax paid, by subtracting the total amount paid from the cost of the item:

530 - 500 = 30


Now divide the amount of tax paid by the cost of the item:

30 / 500 = 0.06

Multiply by 100:

0.06 * 100 = 6% tax


7 0
3 years ago
Read 2 more answers
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