Can you walk me through this problem i dont understand it AREA OF POLYGONS

Mathematics

1 answer:

Mamont248 [21]3 years ago

6 0

The area of a paralellogram is bh

each dimention is multiplied by n
b turns to bn
h turns to hn

bh turns to (bn)(hn) or bnhn or bhn²

expression is bhnn or bhn² or bhn^2 (depends if the program will let you enter the exponent)

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What is the product of three square root of eight times four square root of three? Simplify your answer.

igor_vitrenko [27]

$The\ product\ of 3 \sqrt{8}*4 \sqrt{3}\ is\ 24 \sqrt{6}.$

First, recognize that all the numbers can be moved around because they are being multiplied together.
Next, rearrange the expression so that the whole-number coefficients are together:

$3\sqrt{8}*4\sqrt{6}$
$3*4*\sqrt{8}*\sqrt{3}$

Now try to simplify the square-roots to find any squares inside that can be reduced and taken out of the square-root:

$3*4*\sqrt{(2*2*2)}*\sqrt{3}$
$3*4*\sqrt{4*2}*\sqrt{3}$

Multiply the square roots together:
$3*4*\sqrt{(4*2*3)}$
$3*4*\sqrt{(4*6)}$

Now take out the square-root of 4 and simplify
$3*4*\sqrt{4}*\sqrt{6}$
$3*4*(2)*\sqrt{6}$
$24\sqrt{6}$

$Thus,\ your\ answer\ is\ 24\sqrt{6}$