5×3|12
5×1|4
5|4
1
1--,1.25
4
The answer would be (14,7).
Answer:
q(r(4)) = -61
Step-by-step explanation:
q(x) = -2x +1
r(x) = 2x^2 - 1
q(r(4))
First find r(4)
f(4) = 2 (4)^2 -1
= 2 *16 -1
= 32-1
= 31
Then put this value in for x in q(x)
q(r(4)) = q(31) = -2(31)+1
= -62+1
= -61
12+30>6x-4x
42>2x
42/2>x
21>x
Answer:
Whenever .
Step-by-step explanation:
We can play around with some numbers and develop some rules for this equation.
Note that the number 5 and -5 are used here, so let's try using 5 as a.
So 5 works. Let's try a random number like 3.
Okay, with this info we know that we might be able to develop one rule that . Just to test, let's try 0, -3, and -5.
Zero works.
-3 works.
-5 works. Now, this might stop here making the equation , so let's test a number outside of -5 - say -20.
Yes! This works, so a works for this equation as long as .
Hope this helped!