No she is not correct as 43 is a prime number. It is an odd number though.
Answer:
D.)
Step-by-step explanation:
The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts. You can graph the function and see when the graph crosses the x-axis or solve for the x-values. I will solve it via factoring and so:

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6. Now let's think about all the factors of 6 we have: 6×1 and 2×3. Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5? Actually we can say 6-1=5 and 2+3=5. Let's try both.
First let's use 6 and -1 and so:

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.
Now let's try 2 and 3 and so:

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:
Case 1:

Case 2:

So your zero's are when x=-2 and x=-3.
D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.
~~~Brainliest Appreciated~~~
The number added to the polynomial by completing the square is 
Explanation:
Given that the polynomial is 
We need to determine the number that is added to the polynomial to complete the square.
The last term of the polynomial can be determined by dividing the term 17 by 2 and then squaring the term.
Thus, we have,
Last term = 
Now, squaring the term, we have,
Last term = 
Thus, the number added to the polynomial by completing the square is 
4/5 = 28/x
You need to multiply 4 by how many times to get 28?
4.y = 28
y = 28/4
y = 7
So, you need to multiply 5 by 7 to know x.
x = 5.7
x = 35
4/5 = 28/35