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Soloha48 [4]
3 years ago
10

Find the slope and reduce. P=(-2, -1) Q=(6,5) Slope = [ ? ]

Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0

Answer:

Slope=3/4

Step-by-step explanation:

1) Label all values with x1 y1, x2 y2

Then, plug jn each value into this equation:y2-y1/x2-x1

Remember that negative values will become positive when dealjng with a subtraction sign.

5-(-1)=5+1.

---------------= 6/8

6-(-2)=6+2

After getting 6/8, simplify by the gcf (2) to get 3/4

Answer:3/4

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A triangle has sides with lengths of 5 meters, 6 meters, and 8 meters. Is it a right triangle?
Sever21 [200]

Answer:

No, it is not a right triangle

Step-by-step explanation:

A scalene right triangle comprised of integers must have the same ration as 5:4:3, and 5:6:8 is not it.

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2 years ago
A box without a top is made from a rectangular piece of cardboard, with dimensions 27 centimeters by 18 centimeters, by cutting
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By cutting each corner we have that the resulting dimensions are:
 27 - 2x
 18 - 2x
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 V (x) = (x) * (27-2x) * (18-2x)
 Answer:
 
The volume of the box in terms of x is:
 
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3 years ago
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3s+2t−3 =c<br> −7s−5t =4<br> ​
irinina [24]

Answer:

c=

−4

3

s−t+

−4

3

Step-by-step explanation:

Let's solve for c.

3s+2t−3c−7s−5t=4

Step 1: Add 4s to both sides.

−3c−4s−3t+4s=4+4s

−3c−3t=4s+4

Step 2: Add 3t to both sides.

−3c−3t+3t=4s+4+3t

−3c=4s+3t+4

Step 3: Divide both sides by -3.

−3c

−3

=

4s+3t+4

−3

c=

−4

3

s−t+

−4

3

3 0
3 years ago
A customer tells you that they will call at 3PM Eastern Standard Time. If you are located in the Pacific Standard Time Zone (whi
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Determine if each of the following sets is a subspace of Pn, for an appropriate value of n.
snow_tiger [21]

Answer:

1) W₁ is a subspace of Pₙ (R)

2) W₂ is not a subspace of Pₙ (R)

4) W₃ is a subspace of Pₙ (R)

Step-by-step explanation:

Given that;

1.Let W₁ be the set of all polynomials of the form p(t) = at², where a is in R

2.Let W₂ be the set of all polynomials of the form p(t) = t² + a, where a is in R

3.Let W₃ be the set of all polynomials of the form p(t) = at² + at, where a is in R

so

1)

let W₁ = { at² ║ a∈ R }

let ∝ = a₁t² and β = a₂t²  ∈W₁

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t²) + c₂(a₂t²)

= c₁a₁t² + c²a₂t²

= (c₁a₁ + c²a₂)t² ∈ W₁

Therefore c₁∝ + c₂β ∈ W₁ for all ∝, β ∈ W₁  and scalars c₁, c₂

Thus, W₁ is a subspace of Pₙ (R)

2)

let W₂ = { t² + a ║ a∈ R }

the zero polynomial 0t² + 0 ∉ W₂

because the coefficient of t² is 0 but not 1

Thus W₂ is not a subspace of Pₙ (R)

3)

let W₃ = { at² + a ║ a∈ R }

let ∝ = a₁t² +a₁t  and β = a₂t² + a₂t ∈ W₃

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t² +a₁t) + c₂(a₂t² + a₂t)

= c₁a₁t² +c₁a₁t + c₂a₂t² + c₂a₂t

= (c₁a₁ +c₂a₂)t² + (c₁a₁t + c₂a₂)t ∈ W₃

Therefore c₁∝ + c₂β ∈ W₃ for all ∝, β ∈ W₃ and scalars c₁, c₂

Thus, W₃ is a subspace of Pₙ (R)

8 0
3 years ago
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