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8_murik_8 [283]
3 years ago
13

What is the sum? StartFraction 3 Over x EndFraction + StartFraction 4 Over x squared EndFraction StartFraction 3 x + 4 Over x cu

bed EndFraction StartFraction 7 Over x EndFraction StartFraction 3 x + 4 Over x squared EndFraction StartFraction 7 Over x + x squared EndFraction
Mathematics
2 answers:
scZoUnD [109]3 years ago
6 0

Answer:

Third option:

StartFraction 3 x + 4 Over x squared EndFraction

Step-by-step explanation:

3/x + 4/x²

LCM: x²

(3×x + 4)/x²

(3x + 4)/x²

vfiekz [6]3 years ago
4 0

Answer:

StartFraction 3 Over x EndFraction + StartFraction 4 Over x squared EndFraction

Step-by-step explanation:

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If figure 1 has 4 tiles, fig 2 has 10, and fig 3 has 16... What is my rule?
Sever21 [200]

Answer:

Add 6 each time.

Step-by-step explanation:

Figure 1 has 4 tiles.

To go from figure 1 (4 tiles) to figure 2 (10 tiles), you added 6 tiles.

To go from figure 2 (10 tiles) to figure 3 (16 tiles), you added 6 tiles.

∴ the rule is to add 6 tiles each time.

7 0
3 years ago
What is the value of the 9th term in the following geometric sequence?
earnstyle [38]

Answer:  The correct option is (D) 196608.

Step-by-step explanation:  We are given to find the value of the 9th term in the following geometric sequence :

3,     12,    48,    192,    .     .     .

We know that

the n-th term of a geometric sequence with first term a and common ratio r is given by

a_n=ar^{n-1}.

For the given sequence, we have

first term, a = 3  and the common ratio, r is given by

r=\dfrac{12}{3}=\dfrac{48}{12}=\dfrac{192}{48}=~~.~~.~~.~~=4.

Therefore, the 9th term of the given sequence will be

a_9=ar^{9-1}=3\times 4^8=3\times65536=196608.

Thus, the required 9th term of the given sequence is 196608.

Option (D) is CORRECT.

7 0
3 years ago
A manufacture inspects 800 light bulbs and finds that 796 of them have no defects. What is the experimental probability that a l
BartSMP [9]

Answer:

The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.

Step-by-step explanation:

let S be the sample space for the inspection of the light bulbs.

Therefore, n(s) = 800

let ' A ' be the event of no defects bulbs.

Therefore, n(A) = 796

Now the Experiment probability for a light bulb chosen has no defects will be given by,

P(A)=\dfrac{n(A)}{n(S)}

Substituting the values we get

P(A)=\dfrac{796}{800}=0.995

The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.

3 0
3 years ago
Not good at this big time
alexgriva [62]
You are doing great!
7 0
2 years ago
8 different type of numbers?
brilliants [131]

Answer:

Disclaimer: You can disregard some if not wanted information.

1. decimal's

2. Exponent's

3. Variable's (still counts)

4. rational number's

5. Irrational Number's

6. Repeating Decimal's

7.Terminating decimal's

8.Integer's

One Honorable Mention:

Fraction's

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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