Pleaseeeeeeeeeeeeeeeeeeee helppppppppppppppp

Please help! I dont understand! Thank you

Digiron [165]

QUESTION A

The given inequality is

$x-1\:>\:5$

Add 1 to both sides of the inequality to obtain;

$x\:>\:5+1$

$x\:>\:6$

Answer: 2. $x\:>\:6$ , open dot at 6 and shaded to the right.(A)

QUESTION B.

The given inequality is $2x \le 6$ .

Divide both sides by 2;

$x \le \frac{6}{2}$ .

$x \le 3$ .

Answer: 5. $x \le 3$ , closed dot at 3 and shaded to the left(B).

QUESTION C

The given inequality is $x-7\:>\:-4$

Add 7 to both sides to get;

$x\:>\:-4+7$

$\Rightarrow x\:>\:3$

Answer: 7. $x\:>\:3$ , open dot at 3 and shaded to the right.(C)

QUESTION D

We want to solve;

$-2x \:$

Divide through by -2 and reverse the inequality sign;

$x \:>\:\frac{6}{-2}$

$x \:>\:-3$

Answer; 3. $x \:>\:-3$ Open dot at -3 and shaded to the right. (D)

QUESTION E

We have

$4\:$

Divide through by -4 and reverse the sign.

$\frac{4}{-4}\:>\:x$

$-1\:>\:x$

or

$x\:$

Answer: 6. $x\:$ open dot at -1, and shaded to the left(E)

QUESTION F

The given inequality is $-2x+3\:$

Add -3 to both sides to get;

$-2x\:$

Divide both sides of the inequality by -2 and reverse the sign;

$x\:>\:5$

Answer:9. $x\:>\:5$ , open dot at 5 and shaded to the right(F)

QUESTION G

The given inequality is

$5x+1\ge11$

$5x\ge11-1$

$5x\ge10$

Divide by 5

$x\ge2$

Answer ; 10. $x\ge2$ , closed dot at 2 and shaded to the right(G)

QUESTION H

We have $3(x+4)\:>\:8x-6$

Expand the bracket to get;

$3x+12\:>\:8x-6$

Group similar terms to get;

$3x-8x\:>\:-6-12$

Simplify

$-5x\:>\:-18$

Divide through by -5 and reverse the sign;

$x\:$

Answer: 1. $x\:$ Open dot at 18/5 and shaded to the left(H)

QUESTION I

We have $-3x+4\:$ .

$-3x+x\:$

$-2x\:$

Divide by -2 and reverse the sign;

$x\:>\:1$

Answer: 8. $x\:>\:1$ , open dot at 1 and shaded to the right(I)

J. The given inequality $-2(x-4)\:>\:5-(x+2)$

Expand the bracket to get;

$-2x+8\:>\:5-x-2$

Group like terms to get;

$-2x+x\:>\:5-2-8$

$-x\:>\:-5$

Divide by -1 and reverse the sign to get;

$x\:$

Answer; 4. $x\:$ , open dot at 5 and shaded to the left.(J)

6 0

4 years ago

For the high school's production of "Grease," 490 tickets were sold. The cost of a student

damaskus [11]

The system of equations could be used to determine the number of each type of ticket sold is:

s + p + t = 490

8s + 10p + 12t = 4600

s + p = 6t

Number of each type of ticket sold is:

number of student tickets sold = 220

number of pre-sale non student ticket sold = 200

number of ticket sold at door = 70

Solution:

Let "s" be the number of student tickets sold

Let "p" be the number of pre-sale non student ticket sold

Let "t" be the number of ticket sold at door

Cost of 1 student ticket = $ 8

Cost of 1 pre-sale non student ticket = $ 10

Cost of 1 ticket sold at door = $ 12

From given information,

490 tickets were sold. So we can frame a equation as:

number of student tickets sold + number of pre-sale non student ticket sold + number of ticket sold at door = 490

s + p + t = 490 ---------- eqn 1

Also given that, The total income from ticket sales was $4600

So we can frame a equation as:

number of student tickets sold x Cost of 1 student ticket + number of pre-sale non student ticket sold x Cost of 1 pre-sale non student ticket + number of ticket sold at door x Cost of 1 ticket sold at door = $ 4600

$s \times 8 + p \times 10 + t \times 12 = 4600$

8s + 10p + 12t = 4600 ------ eqn 2

The combined number of student and pre-sale tickets was 6 times more than the tickets sold at the door

s + p = 6t --------- eqn 3

So eqn 1 eqn 2 and eqn 3 could be used to determine the number of each type of ticket sold

Let us solve eqn 1, eqn 2, eqn 3 to find values of "s" "p" and "t"

Substitute eqn 3 in eqn 1

6t + t = 490

7t = 490

Substitute t = 70 in eqn 2

8s + 10p + 12(70) = 4600

8s + 10p = 3760 ----- eqn 4

Substitute t = 70 in eqn 3

s + p = 6(70)

s + p = 420 ----- eqn 5

Multiply eqn 5 by 8

8s + 8p = 3360 ----- eqn 6

Subtract eqn 6 from eqn 4

8s + 10p = 3760

8s + 8p = 3360

(-) ---------------------

2p = 400

Substitute p = 200 in eqn 5

s + 200 = 420

Summarizing the results:

number of student tickets sold = 220

number of pre-sale non student ticket sold = 200

number of ticket sold at door = 70

3 0

3 years ago

Lila is ordering photos online. Each photo cost $0.08, and there is a shipping charge of $4.00 how many photos can Lila order fo

Nitella [24]

$16.00 /.08 = 200 photos

5 0

4 years ago

Julia opened a new flower shop, and her daily sales are modeled by f(x) = 2(1.25)x. Determine the rate of growth.

hammer [34]

Answer:

D. 25%

Step-by-step explanation:

Each day, Julia's sales are 1.25 times the previous day's sales. That is, 25% more than the day before. Julia's sales are increasing 25% per day.

8 0

3 years ago

Read 2 more answers

HELP PLEASE NOBODYS HELPING ME ALL MY POINTS TO YOU

kirill115 [55]

Answer:

5,8,11

10th term = 32

4 0

3 years ago

Read 2 more answers