Answer:
8 and -2
Step-by-step explanation:
Let the numbers be l and s.
We have equations:
l = 5s + 18
3l + 4s = 16
Solve for s by substituting l into the second equation:
3(5s + 18) + 4s = 16
15s + 54 + 4s = 16
19s = 16 - 54
19s = -38
s = -38/19
s = -2
Find the value of l:
l = 5(-2) + 18
l = -10 + 18
l = 8
Answer:
The answer is 1st point
Step-by-step explanation:
(12x²+4x-5)-(9x²-9x+1)
= 12x²+4x-5-9x²+9x-1
= 3x²+13x-6
≥The solution of an inequality is an interval, i.e. a range.
To prove that the interval found as solution, you must consider several cases.
1) In the case that the ineguailty is ≥ or ≤, first use the limits of the interval to prove they are valid solutions. This is, replace the limit values, one at a time, and verifiy the inequality.
2) If the sign is ≥ or > use a value to the right of the limit value to show that the values to the right are solution, and use a value to the left to show that they are not solution.
3) If the sign is ≤ or <, use a value to the left of the limit value to show that it is a solution and a value to the right of the limit value to show that it is not a solution.
Answer:
y = - 5x² - 10x + 2
Step-by-step explanation:
y = - 5(x + 1)² + 7 ← expand (x + 1)² using FOIL
= - 5(x² + 2x + 1) + 7 ← distribute parenthesis by - 5
= - 5x² - 10x - 5 + 7 ← collect like terms
= -5x² - 10x + 2 ← in standard form