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Liula [17]
3 years ago
12

Solve 8z + 12 = 5z − 21

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0
z = -11

Steps:
8z+12 = 5z-21
Subtract 12 from both sides
8z+12-12 = 5z-21-12
Simplify
8z = 5z-33
Subtract 5z from both sides
8z-5z = 5z-33-5z
Simplify
3z = -33
Divide both sides by 3
3z/3 = -33/3
Simplify
z = -11

Hope this helps you! (:
-Hamilton1757
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Hello, hehelol12.

The length of PR is the same as TR.

Length of PR = 11.

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Measure of angle PQR = 39

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3 years ago
Simplify the expression:<br><br> –5(6 − 2y) =
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Furkat [3]
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LCM of x&lt;sup&gt;2&lt;/sup&gt;+5x+6 and x&lt;sup&gt;2&lt;/sup&gt;-x-6 is ………………………
sergejj [24]

Answer:

(x^2 - 9)(x + 2)

Step-by-step explanation:

Given:

x^2 + 5x + 6

x^2 - x - 6

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

x^2 + 5x + 6

x^2 + 3x + 2x + 6

(x^2 + 3x) + (2x + 6)

x(x + 3) + 2(x + 3)

(x + 2)(x + 3)

x^2 - x - 6

x^2 - 3x +2x - 6

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Step 2: find the product of each factor that is common in both polynomials.

We have the following,

x^2 + 5x + 6 = (x + 2)(x + 3)

x^2 - x - 6 = (x + 2)(x - 3)

The common factors would be: =>

(x + 2) (this is common in both polynomials, so we would take just one of them as a factor.

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(x - 3)

Their product = (x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)

4 0
4 years ago
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