Answer:
(I) (-5) is a zero of P(x)
(II) 5 is a zero of P(x)
(III) (-5/2) is a zero of P(x)
Step-by-step explanation:
<h3>
(I) P(x) = x + 5</h3>
Here, P(x) = x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ x + 5 = 0
∴ x = (-5)
Thus, (-5) is a zero of P(x)
<h3>(II) P(x) = x - 5</h3>
Here, P(x) = x - 5
To find the zeroes of P(x)
let P(x) = 0
∴ x - 5 = 0
∴ x = 5
Thus, 5 is a zero of P(x)
<h3>(III) P(x) = 2x + 5</h3>
Here, P(x) = 2x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ 2x + 5 = 0
∴ 2x = -5
∴ x = (-5/2)
Thus, (-5/2) is a zero of P(x)
<u>-</u><u>TheUnknownScientist</u>
Answer: They are similar but not congruent.
Step-by-step explanation: hope this help
Answer: The third choice
Step-by-step explanation:
For the equation of a circle, you would do the opposite signs of the center coordinates and square the radius.
Answer:
ok
Step-by-step explanation:
