1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
Answer:
19 = x
Step-by-step explanation:
The square of the tangent segment = The product of (whole secant segment) (the outside part of the secant segment)
BD²= (BA)(BE)
8² = (4 + x - 7) (4) BA = BE + EB
8² = (x - 3)(4)
64 = 4x - 12
64 + 12 = 4x
76 = 4x
19 = x
Answer:
Answer:
3x + 3y = 0
7x - y = 8
Step-by-step explanation:
The force created by the object is 3.75 Newton.
Given
Mass of the object (m) = 1250 grams
Convert 1250 grams to kilograms by dividing it by 1000.
Mass (m) = 1.25 kg
Acceleration of the body (a) = 3 
From Newton's second law we know 
By Substituting in the above equation we get
Force = 1.25 x 3
Force = 3.75 
It can also be written as force = 3.75 N
Hence Force created by the body is 3.75 Newton.
To know more about Force refer
brainly.com/question/13191643?referrer=searchResults
In points form the answer is (-8,-4) and in equation form the answer is x=-8, y=-4
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