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zheka24 [161]
3 years ago
15

Write a paragraph comparing the distribution of dollars spent on monthly entertainment by 12-year-old girls and boys. Including

your response measures of shape, center, and spread in reference to the context of data presented
Mathematics
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

Veaca dom vetta me lato da la te amo lattea.

Step-by-step explanation:

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I need help it for a dcp
Artyom0805 [142]

Answer:

what grade level is this

5 0
3 years ago
13=5+2(x-17) <br><br> Help me pls
ozzi
<h3><u>The value of x is equal to 21.</u></h3>

13 = 5 + 2(x - 17)

<em><u>Distributive property.</u></em>

13 = 5 + 2x - 34

<em><u>Add 34 to both sides.</u></em>

47 = 5 + 2x

<em><u>Subtract 5 from both sides.</u></em>

42 = 2x

<em><u>Divide both sides by 2.</u></em>

x = 21

3 0
3 years ago
Please help, 50 points! :) Please do all parts <br>you WILL get brainiest<br><br>PDF attached below
Eduardwww [97]

1. The first step here is to arrange the data set's form least to greatest,

Sherelle:  26, 39, 56, 58, 60, 62, 65, 66, 66, 68, 71, 72, 72, 73, 74, 75, 81, 83, 84, 85

Venita:  44, 45, 51, 51, 53, 53, 55, 57, 58, 62, 65, 66, 69, 69, 70, 73, 75, 77, 78, 79

Now we can determine our 5 - number summary based on the numbers respective positions.

First Data Set,

<u>(Five - Number Summary) - Minimum : 26, Quartile 1 : 60, Median : 69.5, Quartile 3 : 75, Maximum : 85</u>

Second Data Set,

<u>(Five - Number Summary) - Minimum : 44, Quartile 1 : 53, Median : 63.5, Quartile 3 : 73, Maximum : 79</u>

2. This part is based on your drawings of the box and whisker plots, so you would have to figure that part out by yourself.

3. First off we know that our data set is composed of the years from 1900, so let's rewrite the set based off of the actual year -

Sherelle:  1926, 1939, 1956, 1958, 1960, 1962, 1965, 1966, 1966, 1968, 1971, 1972, 1972, 1973, 1974, 1975, 1981, 1983, 1984, 1985

Venita:  1944, 1945, 1951, 1951, 1953, 1953, 1955, 1957, 1958, 1962, 1965, 1966, 1969, 1969, 1970, 1973, 1975, 1977, 1978, 1979

( a ) Now in Sherelle's defence, she can say that the lowest coin date in her group is 1926, comparative to Venita's group - the lowest coin date in hers being 1944. Therefore, she is more likely to have the 1916 coin, after all that date is the lowest overall in both their data set.

( b ) In Venita defence, she can say that the mean of her data set is lower than the mean of Sherelle's data set. Take a look at the calculations below,

Sherella's Mean : \frac{39336}{20} = \frac{9834}{5} = 1966.8,

Venita's Mean : \frac{39250}{20} = \frac{3925}{2} = 1962.5

( c ) I would say Sherella's bag would most likely contain the 1916 coin. The mean is a prominent factor, but their mean(s) only differ by a very small quantity. That too, Sherella's bag contains the lowest coin in both their groups, and though that is not a prominent factor, it could be that she does have the 1916 coin.

3 0
4 years ago
What is the value of x in the equation 7x + 2y = 48 , when y = 3?
Sindrei [870]
7x+2y=48
7x+2(3)=48
7x+6=48
Subtract 6 on both sides.
7x=42
divide 7 on both sides
x=6
3 0
3 years ago
Read 2 more answers
Plot (1 3/4, 4 1/2) on the coordinate plane.
ASHA 777 [7]

Answer:

Step-by-step explanation:

you put a point on the x axis at almost 2 because it is 1 3/4

then a point on the y axis between 4 and 5 for the 4 1/2

3 0
2 years ago
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