What is the product of 3x(x2 + 4)? O x² + 3x +4 O 3x3 + 4 O 3x3 + 12x 3x² + 12x
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Now, for z to be an integer, the sum x+y must be a divisor of 10.
It has to be a positive divisor since z≥0. Also x≠y.
x≥0 and y≥0 so y can be equal to either 0 or 1. There are 2 solution in this case.
In this case, y can be equal to 0,1, or 2, but for y=1 ⇒ x=1, so there are two solutions.
y can be 0,1,2,3,4 or 5 - 6 solutions
y can be 0,1,2,3,4,5,6,7,8,9,10, but for y=5 ⇒ x=5, so 10 solutions.
2+2+6+10=20 solutions in total.